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3 years ago

What is the slope intercept form of the equation y+18=2(x-1)

Mathematics

1 answer:

statuscvo [17]3 years ago

8 0

<h2>The slope intercept form of the given equation is: y = 2x + ( - 20) </h2>

Step-by-step explanation:

Given,

The equation y + 18 = 2( x - 1)

To write the given equation in the slope intercept form = ?

∴ The equation y + 18 = 2( x - 1)

⇒ y + 18 = 2x - 2

⇒ y = 2x - 2 - 18

⇒ y = 2x - 20

⇒ y = 2x + ( - 20) ..... (1)

We know that,

The equation of slope intercept form,

y = mx + c

Where, m is the sope and c is the y-intercept

∴ The slope intercept form of the given equation is: y = 2x + ( - 20)

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Step-by-step explanation:

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3 years ago

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Stan has a rectangular piece of carpet with an area of 23.4 square meters. The piece of carpet is 13 meters long. What is the wi

Sholpan [36]

Answer:

The breadth of rectangular carpet is 1.8 m.

Step-by-step explanation:

We have,

The area of rectangular carpet that is 23.4 m²
The length of carpet is 13 m.

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= 23.4 = 13 × Breadth

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2 years ago

The price of a tv was decreased by 20% to £1440. What was the price before the decrease?

grigory [225]

Answer:

€7200

Step-by-step explanation:

20%---------1440

100%----------y

y= 100×1440/20

y= 144000/20

y= €7200

price before decrease= €7200

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2 years ago

I have a d in my class but i need it caught up to a b or an a asap so will anyone help me please?

anyanavicka [17]

Answer:

Hey man, it wont work :(

Step-by-step explanation:

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3 years ago

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Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago