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2 years ago

Helppppppppppp I rlly need help

Mathematics

1 answer:

Flura [38]2 years ago

4 0

Answer:

Number 3 5x + 2y =z

Step-by-step explanation:

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Which is the following fraction is the smallest?9/13 ,17/26, 28/39, 33/52

babunello [35]

Answer:

<h3>I THINK ITS A. 9/13 BECAUSE THE QUESTION SAID THAT FRACTION IS THE SMALLEST</h3>

Step-by-step explanation:

I HOPE IT HELPS :)

4 0

3 years ago

Find numbers between -.27 and -.28

Ede4ka [16]

Answer:

that is literally so easy just add some type of fraction

Step-by-step explanation:

-.27 1/10

-.27 2/10

-.27 3/10

etc.

8 0

3 years ago

16. PHYSICS The formula h = 1201 - 16t2 gives the height h in feet of an object 1 seconds after it is shot upward from

Murrr4er [49]

<h3><u>Question:</u></h3>

The formula h = 120t-16t^2 gives the height h in feet of an object t seconds after it is shot upward from Earth's surface with an initial velocity of 120 feet per second. What will the height of the object be after 6 seconds?

<h3><u>Answer:</u></h3>

The height of object after 6 seconds is 144 feet

<h3><u>Solution:</u></h3>

<em><u>The formula that gives the height of an object is:</u></em>

$h = 120t - 16t^2$

Where,

h is the height in feet and t is the time in seconds

To find: height of the object be after 6 seconds

To find the height of the object be after 6 seconds, substitute t = 6

$h = 120 \times 6 -16(6)^2\\\\h = 720 - 16 \times 36\\\\h = 720 - 576\\\\h = 144$

Thus height of object after 6 seconds is 144 feet

3 0

3 years ago

HELP!!!!

OverLord2011 [107]

Answer:

Step-by-step explanation:

You just need the distance formula here. It's very simple to follow:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

which, for us, looks like this:

$d=\sqrt{(13-4)^2+(19-7)^2}$ and

$d=\sqrt{9^2+12^2}$ and

$d=\sqrt{81+144}$ and

$d=\sqrt{225}$ so

d = 15

4 0

3 years ago

The population of a certain species of bird in a region after t years can be modeled by the function P(t)= 1620/1+1.15e^-0.042t

natka813 [3]

Answer:

Step-by-step explanation:

The function is $\frac{1620}{1+1.15e^{-0.042t}}$

To find the maximum population, we need to set t towards infinity to get our answer.

So, we replace time with maximum ( $\infty$ ). Let's check:

$\frac{1620}{1+1.15e^{-0.042t}}\\=\frac{1620}{1+\frac{1.15}{e^{0.042t}}}\\=\frac{1620}{1+\frac{1.15}{e^{0.042(\infty)}}}\\=\frac{1620}{1+\frac{1.15}{\infty}}\\=\frac{1620}{1+0}\\=\frac{1620}{1}\\=1620$

The population of birds approaches 1620 as t goes towards infinity. So we can say the max population of the species is 1620.

Correct answer is A

5 0

3 years ago

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