Answer:
ANSWER
n < - 3 \: or \: n > - 2n<−3orn>−2
EXPLANATION
The given inequality is,
|2n + 5| \: > \: 1∣2n+5∣>1
By the definition of absolute value,
- (2n + 5) \: > \: 1 \: or \: (2n + 5) \: > \: 1−(2n+5)>1or(2n+5)>1
We divide through by negative 1, in the first part of the inequality and reverse the sign to get,
2n + 5 \: < \: - 1 \: or \: (2n + 5) \: > \: 12n+5<−1or(2n+5)>1
We simplify now to get,
2n \: < \: - 1 - 5 \: or \: 2n \: > \: 1 - 52n<−1−5or2n>1−5
2n \: < \: - 6 \: or \: 2n \: > \: - 42n<−6or2n>−4
Divide through by 2 to obtain,
n \: < \: - 3 \: or \: n \: > \: - 2n<−3orn>−2
Answer:
4th option, (cy+b)/a
Step-by-step explanation:
By algebraic manipulation, we add b to both sides, then divide by a to isolate x.
Answer:
Because the sides BO and MA are marked with one line through the middle, which means those sides are congruent, angle A and Angle O are marked with one line, the angles are congruent, and angles W and N are marked with two lines, which means they are congruent. Therefore the triangles are congruent
I don’t think there is a number that does both of those, the factors of 49 are 1, 7, and 49
