Answer:
<h2><u><em>
6. </em></u></h2><h2><u><em>
a. 11 and 2/3 yds. squared</em></u></h2><h2 /><h2><u><em>
b. Yes, the volume of the shed is 11 and 1/3 yards squared and what she's trying to put into it is only 10 yards squared, if put in properly, it will be able to fit.</em></u></h2><h2 /><h2><u><em>
7. 1,110 in. squared</em></u></h2>
Step-by-step explanation:
6.
a.
(10/3)*(14/9)*(9/4)
= 11 2/3
b.
Yes, because the volume of the shed is about 11.67 yards long, the 10 yards of wood will fit in the shed.
7.
For this one, we have to break it into two pieces.
(I made them into a small box and and big box)
The measurements of the small box are 7*5*6.
The measurements of the big box are 20*5*9.
Using this information, we can make the following equation and solve it quickly.
(7*5*6) + (20*5*9)
(210) + (900)
1,110
Thus, the volume of this box is 1,110 in. ^2
Y=3.5x
Pts are (1,3.5),(2,7),(3,10.5)
Answer:
c
Step-by-step explanation:
the graph is inconsistent
Answer:
cubic units
Step-by-step explanation:
We are to find the volume of the solid of revolution formed by rotating about the x--axis the region bounded by the given curves.
f(x)=2x+1, y=0, x=0, x=4.
The picture is given as shaded region.
This is rotated about x axis
Limits for x are already given as 0 and 4
f(x) is a straight line
The solid formed would be a cone
Volume = ![\pi \int\limits^a_b {(2x+1)^2} \, dx \\= \pi \int\limits^4_0 {(4x^2+4x+1)} \, dx \\=\pi [\frac{4x^3}{3} +2x^2+x]^5_0\\\\=\pi[\frac{4*4^3}{3}+2*4^2+4-0]\\=\frac{364\pi}{3}](https://tex.z-dn.net/?f=%5Cpi%20%5Cint%5Climits%5Ea_b%20%7B%282x%2B1%29%5E2%7D%20%5C%2C%20dx%20%5C%5C%3D%20%5Cpi%20%5Cint%5Climits%5E4_0%20%7B%284x%5E2%2B4x%2B1%29%7D%20%5C%2C%20dx%20%5C%5C%3D%5Cpi%20%5B%5Cfrac%7B4x%5E3%7D%7B3%7D%20%2B2x%5E2%2Bx%5D%5E5_0%5C%5C%5C%5C%3D%5Cpi%5B%5Cfrac%7B4%2A4%5E3%7D%7B3%7D%2B2%2A4%5E2%2B4-0%5D%5C%5C%3D%5Cfrac%7B364%5Cpi%7D%7B3%7D)
Answer:infinite both can e simplifies
Step-by-step explanation:
