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Mariulka [41]
3 years ago
8

. Larry solved this equation. 3(2-3)= x Which representation could Larry have used to solve this equation?

Mathematics
1 answer:
Neko [114]3 years ago
5 0

Answer:

x = -3

Step-by-step explanation:

Given the expression solved by Larry as;

3(2-3) = x

We are to find the equivalent expression x

Using the distributive law;

3(2) - 3(3) = x

6 - 9 = x

-3 = x

Swap

x = -3

Hence Larry could use the distributive law to solve the expression

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The value of the car is 0.94 times the value of the car the previous year.



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Three vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.
topjm [15]

Given:

The three vertices of a parallelogram are (-3,8), (4,5), (2,-5).

To find:

The fourth vertex of the parallelogram.

Solution:

Let the vertices of the parallelogram are A(-3,8), B(4,5), C(2,-5) and D(a,b).

We know that, diagonals of a parallelogram bisect each other. It means midpoints of both diagonals are same.

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Two diagonals of ABCD are AC and BD.

Midpoint of AC = Midpoint of BD

\left(\dfrac{-3+2}{2},\dfrac{8-5}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)

\left(\dfrac{-1}{2},\dfrac{3}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)

On comparing both sides, we get

\dfrac{4+a}{2}=\dfrac{-1}{2}

4+a=-1

a=-1-4

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And,

\dfrac{5+b}{2}=\dfrac{3}{2}

5+b=3

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Therefore, the coordinates of fourth vertex are (-5,-2).

3 0
2 years ago
What is 2/6 x 3/9 i need help
Ira Lisetskai [31]

Answer:1/9

Step-by-step explanation:

Simplified:

1/3 x 1/3

1/9

3 0
3 years ago
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Assume that a policyholder is four times more likely to file exactly two claims as to file exactly three claims. Assume also tha
kykrilka [37]

Answer:

1.3125

Step-by-step explanation:

Given that our random variable X follows a Poisson distributionP(X=k)=\frac{\lambda^k e^-^p}{k!} \ \ \ \ \ \ \ \ p=\lambda

Evaluate the formula at k=2,3:

P(X=2)=0.5\lambda^2e^{-\lambda}\\\\P(X=3)=\frac{1}{6}\lambda^2e^{-\lambda}

#since

4P(X=2)=P(X=3);\\\\0.5\lambda^2e^{-\lambda}=4\times\frac{1}{6}\lambda^3e^{-\lambda}\\\\0.5\lambda^2=\frac{2}{3}\lambda^3\\\\0.75=\lambda

The mean and variance of the Poisson distributed random variable is equal to \lambda:

\mu=\lambda=0.75\\\sigma ^2=\lambda=0.75

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4 0
3 years ago
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