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Sergio039 [100]

3 years ago

7

The graph of a proportional relationship is given along with an equation for a

1 answer:

Oksi-84 [34.3K]3 years ago

7 0

Answer:

im not sure i think its a though..but then again i may be wrong.

Step-by-step explanation:

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

Read 2 more answers

Can someone help me with these two? Please

avanturin [10]

For 16/18 it would be 8/9
For 10/15 it would be 2/3

4 0

3 years ago

Read 2 more answers

*PLEASE HELP* *ANY IRRELEVANT ANSWERS WILL BE REPORTED AS SPAM*

drek231 [11]

Answer:

67.307

Step-by-step explanation:

30×25=750

100×80=8000

750+8000=8750

8750/130=67.307... total hits divided by total games

8 0

2 years ago

Read 2 more answers

In ΔMNO, m = 50 cm, o = 35 cm and ∠O=83°. Find all possible values of ∠M, to the nearest degree.

Alexxandr [17]

Answer:

No solution

Step-by-step explanation:

I got it right on delta math, just dont write anything and turn that in and it should be correct.

7 0

3 years ago

Mr. Noel borrowed money from his cousin at a rate of 10% simple interest. After 1 year, $440

Alborosie

Answer:

<h2>$400</h2>

Step-by-step explanation:

Using the formula for calculating the simple interest expressed as;

Simple Interest = Principal * rate * time/100

Note that the principal is the amount he originally borrowed

I = PRT/100 ............ 1

Amount paid off A = Principal+Interest

A = P+I ............ 2

From equation 2; I = A-P......... 3

Substitute equation 3 into 1;

A-P = PRT/100

Given A = $440, R = 10%, Time = 1year

Substitute the given parameters into the resulting equation;

440 - P = P*10*1/100

440-P = 10P/100

440-P = 0.1P

440 = 0.1P+P

440 = 1.1P

Divide through by 1.1;

1.1P/1.1 = 440/1.1

P = $400

<em>Hence the amount Mr Noel originally borrow is $400</em>

5 0

3 years ago