Answer:
The instantaneous velocity of the eagle at the given time is 7.5 m/s.
Step-by-step explanation:
Given;
height of the cliff, h = 125 m
the height at which the eagle is flying, h(t) = 125 + 1.25t²
The velocity of the eagle is given by;
v = dh/dt
v = 2.5t
The instantaneous velocity of the eagle at t = 3 seconds is given by;
v = 2.5(3)
v = 7.5 m/s
Theerefore, the instantaneous velocity of the eagle at t = 3 seconds is 7.5 m/s.
