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Find the hypotenuse (c) of the right triangle.

Aleksandr-060686 [28]

<h2><u>Solution</u>:-</h2>

Hypotenuse (x) of the right triangle = $\sqrt{7² \: + \: 11²}$

Hypotenuse (x) of the right triangle = $\sqrt{49 \: + \: 121}$

Hypotenuse (x) of the right triangle = $\sqrt{170}$

Hypotenuse (x) of the right triangle = 13

The hypotenuse (x) of the right triangle is <u>1</u><u>3</u><u> </u><u>m</u>.

<h3>Hence, option (D) <u>1</u><u>3</u><u> </u><u>m</u> is correct. [Answer]</h3>

4 0

3 years ago

Find the 97th term of the arithmetic sequence

kozerog [31]

<h2>Answer:</h2><h2>The 97th term in the series is 409</h2>

Step-by-step explanation:

The given sequence is 25, 29, 33, ....

The sequence represents arithmetic progression

In an AP, the first term is a1 = 25

The difference between two terms, d = 29 - 25 = 4

To find the 97th term,

By formula, $a_{n} = a_{1} + (n - 1) d$

Substituting the values in the above equation, we get

$a_{97} = 25 + (97 - 1) 4$

= 25 + (96 * 4)

= 25 + 384

= 409

The 97 th term in the given sequence is 409.

3 0

3 years ago

A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria

Kaylis [27]

Answer:

A) The expression for the number of bacteria is $P(t) = 400e^{0.7783t}$ .

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

$P' = kP$

where $P$ stands for the population of bacteria.

Writing $P'$ as $\frac{dP}{dt}$ , we get

$\frac{dP}{dt} = kP$ .

Notice that this is a separable equation, so

$\frac{dP}{P} = kdt$ .

Then, integrating in both sides of the equality:

$\int\frac{dP}{P} = \int kdt$ .

We have,

$\ln P = kt+C$ .

Now, taking exponential

$P(t) = Ce^{kt}$ .

The next step is to find the value for the constant $C$ . We do this using the initial condition $P(0)=400$ . Recall that this is the initial population of bacteria. So,