1/2 + x + 1/6 > = 1
First add the 2 fractions:
1/2 + 1/6 = 2/3
Now you have:
2/3 + x > =1
Subtract 2/3 from both sides:
x >= 1 - 2/3
X > = 1/3
Answer:
angle 1 is 90 degrees because of the kite theorem:
THEOREM: If a quadrilateral is a kite, the diagonals are perpendicular.
angle 2 is 58 degrees because 180-90-32=58 degrees
Step-by-step explanation:
Answer:
84 sq meters
Step-by-step explanation:
1. Approach
In order to solve this problem, one will have to divide the figure up into simple shapes. A picture is attached showing how the shape is divided up for this answer. Find the area of each region, then add up the results to find the total area.
2. Area of Region 1
As one can see, the length of (Region 1), as given is (6), the width is (3). To find the area multiply the length by the width.
Length * width
6 * 3
= 18
3. Area of Region 2
In (Region 2), the length is given, (12). However, one must find the width, this would be the size of the total side, minus the width of (Region 1). Multiply the length by the side to find the area.
Length * width
= 12 * (8 - 3)
= 12 * 5
= 60
4. Area of Region 3
In (Region 3), the length of the figure is (2), the width is (3). To find the area, multiply the length by the width.
Length * width
= 2 * 3
= 6
5. Total area
Now add up the area of each region to find the total rea,
(Region 1) + (Region 2) + ( Region 3)
= 18 + 60 + 6
= 84
Answer:
B. ![(2, -\frac{5}{2})](https://tex.z-dn.net/?f=%20%282%2C%20-%5Cfrac%7B5%7D%7B2%7D%29%20)
Step-by-step explanation:
Given:
(2, 4) and (2, -9)
Required:
Midpoint of the vertical line with the above endpoints
Solution:
Apply the midpoint formula, which is:
![M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})](https://tex.z-dn.net/?f=%20M%28%5Cfrac%7Bx_1%20%2B%20x_2%7D%7B2%7D%2C%20%5Cfrac%7By_1%20%2B%20y_2%7D%7B2%7D%29%20)
Where,
(2, 4) = (x_1, y_1)
(2, -9) = (x_2, y_2)
Plug in the values into the equation:
![M(\frac{2 + 2}{2}, \frac{4 + (-9)}{2})](https://tex.z-dn.net/?f=%20M%28%5Cfrac%7B2%20%2B%202%7D%7B2%7D%2C%20%5Cfrac%7B4%20%2B%20%28-9%29%7D%7B2%7D%29%20)
![M(\frac{4}{2}, \frac{-5}{2})](https://tex.z-dn.net/?f=%20M%28%5Cfrac%7B4%7D%7B2%7D%2C%20%5Cfrac%7B-5%7D%7B2%7D%29%20)
![M(2, -\frac{5}{2})](https://tex.z-dn.net/?f=%20M%282%2C%20-%5Cfrac%7B5%7D%7B2%7D%29%20)
Answer: I think it’s D
Explanation: