Answer:
The only solution can be (0,-3) point.
Step-by-step explanation:
We have to judge whether the points in options are the solution to the graphed inequality or not.
The first point is (5,-5) which not included in the shaded region of the graph. Hence, it can not be a solution.
The second point is (6,0) which not included in the shaded region of the graph. Hence, it can not be a solution.
The third point is (0,-5) which not included in the shaded region of the graph. Hence, it can not be a solution.
The fourth point is (0,-3). It is on the firm red line which is included in the shaded region of the graph. Hence, it is a solution.
Therefore, the only solution can be (0,-3) point. (Answer)
The answer in the problem will be B I believe
There is no outliers though 102 and 9 are the furthest numbers from the rest, but not a significant outlier
Answer:
a) 46.98%
b) increasing rate of change
Step-by-step explanation:
In year 1987, investment worth $29800
In year 1997, investment worth $43800
Rate of change = 1997investment - 1987investment / 1987investment × 100
Rate of change = 43800 - 29800/29800 × 100
= 14000/29800 × 100
= 0.46979 × 100
= 46.98%
Therefore, the rate of change of the investment during the time period is 46.98%.
b) The rate of change of the investment is increasing. This is as a result of the following reasons. First, the value of rate of change is positive. Second, there is no value for rate of change for period before the time period so we cannot compare rate of change.
