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3 years ago

I need help plz I don’t know how to do it

Mathematics

2 answers:

Dovator [93]3 years ago

6 0

The answer is 9m :) good luck!

Oksanka [162]3 years ago

6 0

9m because if you multiply 3 times 3 it will give you 9.

Hope this helps :)

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Help me please and thank you

Vlad1618 [11]

Answer:

-2

Step-by-step explanation:

The formula to find the slope of two points is $\frac{y_2-y_1}{x_2-x_1}$ . Now, we plug in the values of (8,-6) and (11,-12) and simplify.

$\frac{(-12)-(-6)}{(11)-(8)}$
$\frac{-12+6}{3}$
$\frac{-6}{3}$
$-2$

Therefore, the slope is -2.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0

3 years ago

Find the area of the figure, in square meters, to 1 decimal place.

alukav5142 [94]

Answer:

Where is the picture of the figure

Step-by-step explanation:

6 0

3 years ago

Suppose we conduct a hypothesis test to determine if an exercise program helps people lose weight. We measure the weight of a ra

shusha [124]

Answer: (ii) We reject H0---this sample provides significant evidence that the program is effective.

Step-by-step explanation:

The null hypothesis is

The program is not effective for weight loss.

The alternative hypothesis is

The program is effective for weight loss.

If the P-value for the test turns out to be 0.012, and the level of significance is 0.05, then

Alpha, 0.05 > p value, 0.012

Therefore, there is enough evidence to reject the null hypothesis. We then accept the alternative hypothesis.

The correct option is

(ii) We reject H0---this sample provides significant evidence that the program is effective.

6 0

4 years ago

5. Show that the following points are collinear. a) (1, 2), (4, 5), (8,9)

Irina-Kira [14]

Label the points A,B,C

A = (1,2)
B = (4,5)
C = (8,9)

Let's find the distance from A to B, aka find the length of segment AB.

We use the distance formula.

$A = (x_1,y_1) = (1,2) \text{ and } B = (x_2, y_2) = (4,5)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (2-5)^2}\\\\d = \sqrt{(-3)^2 + (-3)^2}\\\\d = \sqrt{9 + 9}\\\\d = \sqrt{18}\\\\d = \sqrt{9*2}\\\\d = \sqrt{9}*\sqrt{2}\\\\d = 3\sqrt{2}\\\\$

Segment AB is exactly $3\sqrt{2}$ units long.

Now let's find the distance from B to C

$B = (x_1,y_1) = (4,5) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(4-8)^2 + (5-9)^2}\\\\d = \sqrt{(-4)^2 + (-4)^2}\\\\d = \sqrt{16 + 16}\\\\d = \sqrt{32}\\\\d = \sqrt{16*2}\\\\d = \sqrt{16}*\sqrt{2}\\\\d = 4\sqrt{2}\\\\$

Segment BC is exactly $4\sqrt{2}$ units long.

Adding these segments gives

$AB+BC = 3\sqrt{2}+4\sqrt{2} = 7\sqrt{2}$

----------------------

Now if A,B,C are collinear then AB+BC should get the length of AC.

AB+BC = AC

Let's calculate the distance from A to C

$A = (x_1,y_1) = (1,2) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-8)^2 + (2-9)^2}\\\\d = \sqrt{(-7)^2 + (-7)^2}\\\\d = \sqrt{49 + 49}\\\\d = \sqrt{98}\\\\d = \sqrt{49*2}\\\\d = \sqrt{49}*\sqrt{2}\\\\d = 7\sqrt{2}\\\\$

AC is exactly $7\sqrt{2}$ units long.

Therefore, we've shown that AB+BC = AC is a true equation.

This proves that A,B,C are collinear.

For more information, check out the segment addition postulate.

7 0

3 years ago

Which could be the dimensions of a rectangular prism whose surface area is less than 160 square feet? Select two options.

Sloan [31]

Try to do pathegoram theorem and you will find your answer

8 0

3 years ago

Read 2 more answers