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kap26 [50]
2 years ago
13

Find the measure of the missing angles.

Mathematics
2 answers:
kenny6666 [7]2 years ago
8 0

Answer:

e- 77

d- 52

f- 51

Step-by-step explanation:

Bingel [31]2 years ago
3 0

Step-by-step explanation:

d=52° (,vertically opposite angle)

77+52+f=180 (linear pair)

f=180- 129

f=51°

52+51+e=180

e=180- 103

e=77°

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3 /8 + 2/ 3 = 9/ 24 + 16/ 24 = 25/ 24 =
Alchen [17]
Convert the denominator of the first two fractions to 24 since 3 and 8 can fit into 24.

3/8=9/24

2/3=16/24

Now add them together.

9/24+16/24=25/24

Next add the second two fractions 9/24 and 16/24.

9/24+16/24=25/24


Since all fractions equal 25/24, the equation was true!

Hope this helps!

7 0
3 years ago
Division 54 /7.5 plz answer this​
harkovskaia [24]

Answer:

turn the decimal into a whole number by multiplying by 10, 100 (what you do to one number you must do to the other)

multiply both by 10 it then becomes

540/75 = 7.2

it's easier to divide whole numbers and is the same answer as 54/7.5

6 0
3 years ago
Assume you know that a hot-air balloon is currently inflated with a certain amount of air and that the amount is a percent of th
Gemiola [76]

Answer:

<u>Percent air is calculated as:</u>

  • Percent air = Current amount/Total amount *100

<u>Solve for total amount of air:</u>

  • Total amount  = Current amount / Percent air * 100

Substitute the values in hand to get the answer

3 0
3 years ago
The number of guppies that a fish tank can safely hold depends on its volume. A fish tank should have a volume of 576 cubic inch
andre [41]
The answer is 24 guppies. First find the volume of the tank, then divide that volume by 576 (you should get 8), then you multiply 3 guppies by 8 to get 2e
3 0
3 years ago
Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo
kolezko [41]

Let <em>x</em> and <em>y</em> be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2<em>x</em> + <em>y</em> = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

<em>x</em> + 3<em>y</em> = 0.25

Solve for <em>x</em> and <em>y</em>. We have

<em>y</em> = 0.25 - 2<em>x</em>   ==>   <em>x</em> + 3 (0.25 - 2<em>x</em>) = 0.25

==>   <em>x</em> + 0.75 - 6<em>x</em> = 0.25

==>   5<em>x</em> = 0.5

==>   <em>x</em> = 0.1

==>   <em>y</em> = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4<em>x</em> + 4<em>y</em> = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time <em>t</em> to fill one pool, we have

(3/5 pool/hour) (<em>t</em> hours) = 1 pool

==>   <em>t</em> = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

6 0
3 years ago
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