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deff fn [24]
3 years ago
9

Factorise by grouping: x² - 5x + 2x - 10

Mathematics
1 answer:
Natalka [10]3 years ago
6 0

Answer:

\boxed {\boxed {\sf (x+2)(x-5)}}

Step-by-step explanation:

To factor by grouping, first divide the polynomial into 2 groups with parentheses.

x^2-5x+2x-10

(x^2-5x)+ (2x-10)

Factor the greatest common factor (GCF) out of both binomials.

For the first binomial, the GCF is x.

x(x-5) +(2x-10)

For the second binomial, the GCF is 2.

x(x-5)+2(x-5)

Factor out the common binomial which is (x-5).

(x+2)(x-5)

The factorized form of x²-5x+2x-10 is (x+2)(x-5)

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Dmitrij [34]

The second term of the given sequence aₙ = -5(n² + 1n) when solved gives us; a₂ = -20

<h3>How to find the nth term of a sequence?</h3>

We are given the formula for a sequence as;

aₙ = -5(n² + 1n)

Where n is the position of the term.

Now, for the first term, we will have;

a₁ = -5(1² + 1(1))

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The second term of the sequence is;

a₂ = -5(2² + 1(2))

a₂ = -20

Read more about Sequence at; brainly.com/question/6561461

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Nataly [62]

Answer:

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Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

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AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

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Using trigonometric ratio,

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\tan 45^{\circ}=\frac{30}{EA}

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Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

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Step-by-step explanation:

hope we can be friends

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