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Bad White [126]
3 years ago
7

Solve Each Equation 5. -8(5+4x)=-232 6. -84=4(4r+7)

Mathematics
1 answer:
Sever21 [200]3 years ago
8 0

Step-by-step explanation:

<h2>5.</h2>

- 8(5 + 4x) =  - 232

- 40 - 32x =  - 232 \\  - 32x =  - 232 + 40 \\  - 32x =  - 192 \\  \frac{ - 32x}{ - 32}  =  \frac{ - 192}{ - 32}  \\  \\ \huge x = 6

<h2>6.</h2>

- 84 =  4(4r + 7) \\  - 84  =  16r + 28 \\ 16r =  - 84 - 28 \\ 16r =  - 112 \\  \frac{16r}{16}  =  -  \frac{112}{16}  \\  \\  \huge r = 7

Hope this helps you

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Georgetown passed an ordinance that requires a 5-cent water-bottle tax to be charged for every bottle of
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Answer:

c,13

Step-by-step explanation:

Cause if you divide 65 by 5 you get 13. And to check it you can multiply 13 times 5 and you would still get 65. And can I get your g-mail

7 0
3 years ago
Write a function of least degree to model this graph with the final answer in factored form.
gizmo_the_mogwai [7]

Answer 1 maybe

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5 0
3 years ago
HELP PLEASE!!! I need help with 94 if you could show the steps that would be very helpful!
aksik [14]
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.

The answer is 32.

-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)








7 0
3 years ago
In circle R with m angle QRS= 90 and QR= 3 units find the length of arc QS round to the nearest hundredth
Advocard [28]

Answer:

4.71 units

Step-by-step explanation:

The formula for arc length =

2πr × θ/360

From the above question,

r = QR = 3 units

θ = angle QRS= 90 = 90°

The length of the arc is calculated as:

2 × π × 3 × 90/360

= 4.7123889804 units

Approximately to the nearest hundredth = 4.71 units

8 0
3 years ago
Write an equation in y=mx+b form for the following data
fomenos
The equation would be y= -1/2x + 5
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