3 years ago

10) Solve for y: бу – 12 84

Mathematics

1 answer:

marta [7]3 years ago

3 0

Answer:

Y=16

Step-by-step explanation:

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3 years ago

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3 years ago

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Ostrovityanka [42]

Answer:

The correct options are 2 and 4.

Step-by-step explanation:

From the given box plot it is clear that

$\text{Minimum value}=20$

$Q_1=25$

$Median=40$

$Q_3=50$

$\text{Maximum value}=110$

We know that these number divides the data in four equal parts.

$Q_1=25\%$

$Median=50%$

$Q_3=75\%$

25% of the data values lies between 50 and 110. Therefore option 1 is incorrect.

Seventy-five percent of the data values lies between 20 and 50. Therefore option 2 is correct.

It is unlikely that there are any outliers. This statement is not true because the is a huge difference between third quartile and maximum value.

Therefore option 3 is incorrect.

The interquartile range is

$IQR=Q_3-Q_1=50-25=25$

Therefore option 4 is correct.

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Range = Maximum-Minimum

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Therefore option 5 is incorrect.

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3 years ago

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Serjik [45]

It is D you have subtract them

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