All categories

2 years ago

Which angles are neither obtuse angles nor acute angles?

Mathematics

2 answers:

sleet_krkn [62]2 years ago

5 0

Answer:

A right angle is neither Obtuse nor Acute

Step-by-step explanation:

Akimi4 [234]2 years ago

3 0

Answer: Which angles are neither obtuse angles nor acute angles?

You might be interested in

A slow pitch softball diamond is actually a square 60 ft on a side. how far is it from home to second base?

krek1111 [17]

For this case we have a square whose sides are known and equal to 60 ft.
We want to find the diagonal of the square.
For this, we use the Pythagorean theorem.
We have then:
$d^2 = 60^2 + 60^2

d = \sqrt{60^2 + 60^2}

 d = \sqrt{3600 + 3600}

d = \sqrt{2*3600}

d = 60\sqrt{2}
$
Answer:
from home to second base it is about:
$d = 60\sqrt{2} feet$

3 0

3 years ago

Mr. Arnold is buying dry-erase markers for his classroom. He already has 7 markers. Mr. Arnold buys 5 packs with 7 markers each

klemol [59]

Answer: 7+5(7)+8(4)-2

Step-by-step explanation:

that’s the answer

3 0

2 years ago

If y varies directly as x and y=32 when x=4 find the value of y when x=5

Alex Ar [27]

Answer:

y=40

Step-by-step explanation:

32 divided by 4 equals 8. And 5 times 8 equals 40.

3 0

2 years ago

Plss help i beg you!

frosja888 [35]

Answer:

Step-by-step explanation:

<u>Given expression:</u>

3(x + y) +2x² + (1 + y)²

<u>Find its value when x = 4 and y = 1, substitute:</u>

3(4 + 1) + 2*4² + (1 + 1)² =
3*5 + 2*16 + 2² =
15 + 32 + 4 =
51

7 0

2 years ago

The side length of a square ice cube is claimed to be 1.0 inches, correct to within 0.001 inch. Use linear approximation to esti

Olenka [21]

Answer:

0.012

Step-by-step explanation:

Linear approximation says that,

$f(x) \approx f(x_o)+f'(x_o)(x-x_o)$

For a cube the surface area is $6x^2$ .

So the side is 1.0 inch in, the surface area is $=6\times1^2 = 6$ square inches.

In Linear approximation means you ignore the term $x_o^2$ , if $x_o$ is a small number, because then $x_o^2$ will be a very smalle number and that does not contribute much to the error.

So the surface area is approximately,

$6x^2=6x_o^2+12x_o(x-x_o)$

So here, $x=1.001, x_o=0.001$

The error in the area is approximately,

$12 \times 0.001=0.012$

So the error is 0.012.

3 0

2 years ago