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3 years ago

This graph shows the result of a test designed to measure the stopping power of a certain brand of brake pads.

Biology

1 answer:

blagie [28]3 years ago

6 0

Answer:

i donnnnnnnnnnnnnnntttttttt knowwwwwwwwwwwwwwww

Explanation:

i really dont know im just a 12 year old kid struggling with math

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Why is it important for DNA to be duplicated before mitosis?

natima [27]

If it didn't, one cell would end up with the original DNA, the other wouldn't be a functional cell, because it would lack DNA. If the DNA was split between the two cells, neither cell would have a complete copy. send me a message
Hope this helps!

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4 years ago

Abiotic factors found and needed in biome,and how they are used by biotic factors

yan [13]

Abiotic factors are anything nonliving that help biotic, or living things. Abiotic features include wind, water, ice, sand, rocks ,or even things such as temperature. They are nonliving things. Biotic includes all things living such as humans, plants, and animals. All biotic things rely on nonliving abiotic features to survive.

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3 years ago

____________ livestock are produced with extra copies of growth hormone genes to allow them to grow faster and produce meat that

harina [27]

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3 years ago

Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004

Simora [160]

Hardy Weinberg Equilibrium

Explanation:

Hardy Weinberg Equilibrium formula for allelic frequency is: $p+q=1$

Hardy Weinberg Equilibrium formula for genotypic frequency is: $p^2+q^2+2pq=1$

Here, $p$ =frequency of dominant allele

$q$ =frequency of recessive allele

$p^2$ =frequency of dominant genotype

$q^2$ =frequency of recessive genotype

$2pq$ =frequency of heterozygous genotype

frequency of affected individuals=0.0004(given)

here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as: $q^2$ =0.0004

If $q^2$ =0.0004 $q$ will be 0.02;frequency of recessive allele will be 0.02

Using the formula $p+q=1$

$p+0.02=1\\p=1-0.02=0.98$

hence,frequency of dominant allele will be 0.98

Frequency of dominant genotype will be $p^2=(0.98)^2=0.9604$
Frequency of heterozygous genotype will be $2pq=2*0.98*0.02=0.0392$

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4 years ago

The traits for blood type and Rh are the result of the presence or absence of particular on the erythrocytes.g

just olya [345]

Answer: Antigens

Explanation: The ABO system of blood grouping is based on the basis of the type of antigens that are present in the red blood cells. Erythrocytes is another name for the red blood cells. Antigens are molecules that are capable of eliciting immune response. There are two types of antigens: antigen A and B. Blood type A has only antigen A, blood type B has only antigen B, blood type AB has both antigen A and B while blood type O has no antigen (neither A nor B antigen).

Similarly, Rh trait is determined by the presence or absence of rhesus antigen in the erythrocytes. Rhesus antigen is an antigen first discovered in rhesus monkey. Rh+ indicates the presence of rhesus antigen in the red blood cells while Rh- indicates the absence of rhesus antigen in the red blood cells.

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3 years ago