Answer:
C.
Eventually the population would stop increasing or would decrease, due to lack of food and living space.
Explanation:
This can be solved either by using a Punnet Square or you can use the formula (n(n+1))/2, where n is the number of alleles. However, using either method will give you the number of possible genotypes regardless if it's homozygous or heterozygous. If we use the second formula, that will give you 10 possible genotypes. Since you only want to know the number of heterozygous genotypes, you should subtract the number of possible homozygous genotypes. In this case, there are four. That is (A1,A1), (A2,A2), (A3,A3), and (A4,A4). Knowing this, you'd be able to figure out that there are six heterozygous genotypes.
(A1,A2), (A2,A3), (A3,A4), (A1,A4), (A1,A3), (A2,A4)
For vital signs in which the b/p is 112/170, P is 54, Resp. is 12, and patient is semi-responsive, the treatment to most likely benefit the patient would be to request for advanced life support (ALS) during the transport of the patient to the emergency department.
Advanced life support will allow for the intubation of the patient to administer certain medications to improve the patient's condition or prevent him/her from having another cardiac arrest. The patient should not be given nitro and should not be transported in prone position.
Answer:
Because the algea was not strong enough yet to live on its own and had to stay close a water source, where it could get water and sunlight without doing any work.
Explanation:
