Answer:
[g+2/3g-1] ÷ [g^2+2g/6g+2]
g+2/3g-1 × 6g+2/g^2+2g
g+2/3g-1 × 2(3g +1)/g(g+2)
1/ 3g-1 × 2(3g+1)/g
2(3g +1)÷ g(3g-1)
6g+2 ÷[3g^2-g]
Answer:
The quadratic equation is: 
Step-by-step explanation:
If the roots of the quadratic equation are "-6" and "6", then it must have the following factors: 
Therefore, we can write the equation in factor form as:

where a is a real number constant factor. Now, this equation in standard form will look like:

Therefore, using the information about the leading coefficient being "1" (one), we derive that the constant factor
must be "1". The final expression for the quadratic becomes:

Answer: 3A^4 + 13A^2B - A^2C - 22BC - 10B^2 - 4C^2
To find the volume of a box-shaped fish trap, we have to multiply the three dimensions of it:
(1/4 m)* (2/3 m)* (3/5 m)
= (1*2*3)/ (4*3*5) m^(3)
= 6/ 60 m^(3)
= 1/10 m^(3)
= 0.1 m^(3)
The volume of the box-shaped fish trap is 0.1 m^(3).
Hope this is helpful~
Answer:
Perimeter of the rectangle=6x+8 square units
Step-by-step explanation:
Given that area of rectangle is 
Area of rectangle=lw square units




Comparing the above equation with the given area we get
lw=(x+3)(2x+1)
Therefore length=x+3 and width=2x+1
To find the perimeter :
Perimeter of the rectangle=2(l+w) square units




Therefore perimeter of the rectangle=6x+8 square units