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ArbitrLikvidat [17]
4 years ago
15

Five less than two times a number is 11. Which equation could be used to find the number?

Mathematics
1 answer:
Ivenika [448]4 years ago
3 0

Answer: 2b-5=11

Step-by-step explanation: 2b is equivalent to 2 times, and 5 less is the -5

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I need help with this problem
gregori [183]

Answer:

[g+2/3g-1] ÷ [g^2+2g/6g+2]

g+2/3g-1 × 6g+2/g^2+2g

g+2/3g-1 × 2(3g +1)/g(g+2)

1/ 3g-1 × 2(3g+1)/g

2(3g +1)÷ g(3g-1)

6g+2 ÷[3g^2-g]

4 0
3 years ago
Write the quadratic equation whose roots are -6 and 6, and whose leading coefficient is 1 .
SCORPION-xisa [38]

Answer:

The quadratic equation is: y=x^2-36

Step-by-step explanation:

If the roots of the quadratic equation are "-6" and "6", then it must have the following factors:  (x+6)\,\, and \,\,(x-6)

Therefore, we can write the equation in factor form as:

y=a\,(x+6)\,(x-6)

where a is a real number constant factor. Now, this equation in standard form will look like:

y=a\,(x^2+6x-6x-6^2)=a\,(x^2-36)=ax^2-36\,a

Therefore, using the information about the leading coefficient being "1" (one), we derive that the constant  factor a must be "1". The final expression for the quadratic becomes:

y=x^2-36

5 0
4 years ago
(A^2+5B+C)(3A^2-2B-4C)
antoniya [11.8K]

Answer: 3A^4 + 13A^2B - A^2C - 22BC - 10B^2 - 4C^2

6 0
4 years ago
A biologist uses a box-shaped fish trap that measures 1/4 meter by 2/3 meter by 3/5 meter. What is the volume of the trap in cub
Zolol [24]
To find the volume of a box-shaped fish trap, we have to multiply the three dimensions of it: 
(1/4 m)* (2/3 m)* (3/5 m)
= (1*2*3)/ (4*3*5) m^(3)
= 6/ 60 m^(3)
= 1/10 m^(3)
= 0.1 m^(3)

The volume of the box-shaped fish trap is 0.1 m^(3).

Hope this is helpful~
8 0
4 years ago
Read 2 more answers
If a rectangle has an area of 2x^2+7x+3 find the perimeter
Helen [10]

Answer:

Perimeter of the rectangle=6x+8 square units

Step-by-step explanation:

Given that area of rectangle is 2x^2+7x+3

Area of rectangle=lw square units

2x^2+7x+3=2x^2+x+6x+3

=x(2x+1)+3(2x+1)

=(x+3)(2x+1)

2x^2+7x+3=(x+3)(2x+1)

Comparing the above equation with the given area we get

lw=(x+3)(2x+1)

Therefore length=x+3 and width=2x+1

To find the perimeter :

Perimeter of the rectangle=2(l+w) square units

=2((x+3)+(2x+1))

=2(x+3+2x+1)

=2(3x+4)

=6x+8

Therefore perimeter of the rectangle=6x+8 square units

6 0
4 years ago
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