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Gala2k [10]
3 years ago
6

Elsie is going to flip a coin and spin a spinner. The coin has a heads and a tails. The spinner has four equal parts that are ye

llow, blue, red, and green. What are the chances that Elsie gets heads and red on the spinner?
A. 1/8
B. 1/6
C. 1/4
D. 1/2
Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

1/6

Step-by-step explanation:

LUCKY_DIMON [66]3 years ago
4 0
Your answer is B. 1/6
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Zoe's Fish tank holds 27 L of water she uses a 3L container to fill the tank how many times does she have to fill the three litt
Marianna [84]
<h2>Answer:</h2>

Zoe's Fish tank holds 27 L of water, so this is the capacity of the tank. On the other hand, Zoe uses a 3L container in order to fill the tank, so the question is  how many times does she have to fill the three litter container in order to fill the fish tank? Let's solve this as follows:

First time:

She pours 3L

Second time:

She pours another 3L, but she previously poured 3L, so she has poured 6L

Third time:

She pours another 3L, but she previously poured 6L, so she has poured 9L

Fourth time:

She pours another 3L, but she previously poured 9L, so she has poured 12L

Fifth time:

She pours another 3L, but she previously poured 12L, so she has poured 15L

Sixth time:

She pours another 3L, but she previously poured 15L, so she has poured 18L

Seventh time:

She pours another 3L, but she previously poured 18L, so she has poured 21L

Eighth time:

She pours another 3L, but she previously poured 21L, so she has poured 24L

Ninth time:

She pours another 3L, but she previously poured 24L, so she has poured 27L

<em>According to this, she needs to pours the </em><em>3L </em><em>container nine times in order to fill the fish tank. This can also be solved dividing </em><em>27L/3L= 9</em>

4 0
3 years ago
Round 4,204 to the nearest hundred​
Hoochie [10]

Answer:

4200

hope helpful <3 !!!!!!!!!!!!!

8 0
2 years ago
Write the solution to the inequality in set - builder notation:<br> 5r + 8 &lt; 63
Leni [432]
<span>First, the inequality needs to be solved. The first step is to subtract 8 from both sides of the inequality, leading to 5r < 55. Dividing 5 out from both sides, this will leave r < 11. Next, to form a set notation, the inequality is written in such form: {r | r < 11}.</span>
7 0
3 years ago
Helppp asap please!!!!
ss7ja [257]
4/10 and 6/10
(40% and 60%)
3 0
3 years ago
Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4
dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

x_1\ =\ -2

y_1\ =\ 3

z_1\ =\ -4

Distance is measure across the line

\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}

So, we can write

\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k

=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k

=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k

=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3

=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18

=>18k-24+12k+9+10k-32\ =\ 18

=>\ k\ =\dfrac{13}{8}

So,

x\ =\ 3k-4

   =\ 3\times \dfrac{13}{8}-4

   =\ \dfrac{7}{4}

y\ =\ \dfrac{4k+3}{2}

   =\ \dfrac{4\times \dfrac{13}{8}+3}{2}

   =\ \dfrac{19}{4}

z\ =\ \dfrac{5k-16}{3}

  =\ \dfrac{5\times \dfrac{13}{8}-16}{3}

   =\ \dfrac{-21}{8}

Now, the distance of point from the plane is given by,

d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}

   =\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}

   =\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}

   =\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}

   =\ \sqrt{\dfrac{1177}{64}}

   =\ 4.28

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

            = 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0
3 years ago
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