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defon
3 years ago
7

The scale drawing of a rectangular deck has the dimensions of 4 inches by 6 inches. the dimensions of the actual deck are 14 fee

t by 21 feet. what is the scale factor used to find the dimensions of the drawing?
Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0
1 inch : 3.5 feet is the scale.
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How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
What is the area of a sector with a central angle of 3pi/5 radians and a diameter of 21.2cm
Elenna [48]
Answer: 105.84 cm^2

To find the answer, first you have to start by finding the percent of the circle in the sector. Convert the radians given to 108 degrees. 108 out of 360 is 30%. 

Now, find the area of the circle. It's pi x r^2, so the area is 352.810.

Multiply this by 30% to find our area of 105.84 cm^2
8 0
3 years ago
Find the GCF of the terms of the polynomial. 33x^3 + 18^6
Ronch [10]

33x^3=\boxed{3}\cdot11\cdot\boxed{x}\cdot\boxed{x}\cdot\boxed{x}\\\\18x^6=2\cdot\boxed{3}\cdot3\cdot\boxed{x}\cdot\boxed{x}\cdot\boxed{x}\cdot x\cdot x\cdot x\\\\GCF(33x^3,\ 18x^6)=\boxed{3}\cdot\boxed{x}\cdot\boxed{x}\cdot\boxed{x}=3x^3

5 0
4 years ago
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Nimfa-mama [501]
The correct answer is

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3 years ago
Help I need this answer ASAP
gregori [183]

Answer: c

Step-by-step explanation: because yes

4 0
3 years ago
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