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2 years ago

Find tan 0, where is the angle shown. Give an exact value, not a decimal approximation. (PLZ HELP DUE SOON I GIVE BRAINLIST :D)

Mathematics

1 answer:

Gennadij [26K]2 years ago

6 0

Answer:

$\frac{24}{7}$

Step-by-step explanation:

Tanθ=Opposite/Adjacent

we have the adjacent side but need the oppsoite

We will use a²+b²=c²

25²=7²+b²

576=b²

b=24

Therefore the answer is

$\frac{24}{7}$

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2 years ago

Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

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$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

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2 years ago

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3 years ago

Find tan 0, where is the angle shown. Give an exact value, not a decimal approximation. (PLZ HELP DUE SOON I GIVE BRAINLIST :D)​

Find tan 0, where is the angle shown. Give an exact value, not a decimal approximation. (PLZ HELP DUE SOON I GIVE BRAINLIST :D)