Wasnt sure if you were asking just for the standard form of that equation
<span>(15y − 9 + 6y^2) + (10 − 5y) = 0 ) or if you wanted the equation simplified and then in standard form ( 6y^2 + 10y + 1 = 6 ) so i did both </span>
Answer:
Perpendicular
Step-by-step explanation:
Given points P=(2,6) and Q=(4,5)
The line RS is y=2x-3.
Now we know that the line joining any two points (x1,y1) and (x2,y2) has slope m=
Now the slope of the line PQ is
m1=
= -
We know that the slope of the line in the form y=mx+c is m
So the line RS has slope m2=2
Now two lines are parallel if m1=m2
And those two lines are perpendicular if 
here m1= -
and m2=2
clearly 
Therefore the two given lines are perpendicular
The slope of the line
is
.
The line perpendicular to the above line has slope
Its equation is
. Since this line passes through,
,

Thus the equation of the line in slope intercept form is 
The point-slope form:

We have the points (2, 2) and (0, -4). Substitute:

The standard form:

<em>use distributive property</em>
<em>add 6 to both sides</em>
<em>subtract y from both sides</em>

<h3>Answer: 3x - y = 4</h3>
A) 5/2x^3-9/4x^2+7/2x-3/2
b) the ans. are not the same.