I think its only B because it's the only one I see that is enlivenment.<span />
Answer:
nElements = 0;
for (int i = 0; i < a2d.length; i++)
nElements += a2d[i].length;
isRectangular = true;
for (int i = 1; i < a2d.length && isRectangular; i++)
if (a2d[i].length != a2d[0].length)
isRectangular = false;
Step-by-step explanation:
2 dimensional array is created and initialize element with 0. and the taking loop for 2 dimensional array .such as
n Elements = 0;
for (int i = 0; i < a2d.length; i++)
n Elements += a2d[i].length;
A boolean variable isRectangular and 2 dimensional array has been created if rectangle is true the take a2d.length and isRectangular less than i and intiliaze i with 1 then increment the i .It will give true value.
If rectangular is false then apply if statement and see if a2d[i] is not equal to a2d[0]
if (a2d[i].length != a2d[0].length)
isRectangular = false;
Hi there
Simplified form of -(-10p+4r)
10p-4r
You know that if you are multiplying a number by 5, and multiplying the same number by 6, 6 is going to be bigger
The correct answer is D
Hope this helped :)
