Question

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

Answer 1

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

Answer 2

Answer:

The 2010 world-record pumpkin weighs 1810 kilograms more than an average-sized pumpkin.

Step-by-step explanation:                

Given : In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

To find : The 2010 world-record pumpkin weighs _____ kilograms more than an average-sized pumpkin ?

Solution :

An average-sized pumpkin weighs 5,000 grams.

Converting into kilogram,

$1\ kg=1000\ g$

$1\ g=\frac{1}{1000}\ kg$

$5000\ g=\frac{5000}{1000}\ kg$

$5000\ g=5\ kg$

In 2010, the world's largest pumpkin weighed 1,810 kilograms.

Now, we will subtract 5 kg from 1810 kg.

$1810-5=1805\ kg$

Therefore, the 2010 world-record pumpkin weighs 1810 kilograms more than an average-sized pumpkin.