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german
3 years ago
13

PLZ HELP THIS IS FRUSTRATING FOR BRAINLIST

Mathematics
1 answer:
Damm [24]3 years ago
5 0
The first one is 7x^112=7x(12) because you divide both by 7x^112=84x and for the second question 4x6x50=4x^56 as a simplifying strategy to solve not evaluate that’s all I have also Socratic is recommended to help.
You might be interested in
Find |−68|. plz i will give brainlist
Anni [7]

Answer:

68

Step-by-step explanation:

The lines on both sides of the number represent absolute value. Absolute value takes any number and turns it positive no matter what.

|-68| → 68

Best of Luck!

8 0
3 years ago
The length of a rectangle is 6 inches more than its width. Its area is 91 square inches. The length is .
Vika [28.1K]

Answer:

13 in

Step-by-step explanation:

let w be width then length is w + 6

the area (A) of a rectangle is calculated as

A = length × width , then

A = w(w + 6) = 91 , that is

w² + 6w = 91 ( subtract 91 from both sides )

w² + 6w - 91 = 0 ← in standard quadratic form

(w + 13)(w - 7) = 0 ← in factored form

equate each factor to zero and solve for w

w + 13 = 0 ⇒ w = - 13

w - 7 = 0 ⇒ w = 7

however, w > 0 then w = 7

and length = w + 6 = 7 + 6 = 13 in

8 0
2 years ago
I NEED HELP! PLEASE HELP!
Amanda [17]

Answer:

2400 mm

Step-by-step explanation:

(80 x 60) - (60 x 40)

7 0
3 years ago
What is 50,779 divided by 590? Attach work pretty plz
nignag [31]
50,779/590 is 90.7125 but rounded to 90.71
6 0
3 years ago
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
4 years ago
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