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butalik [34]
1 year ago
8

State whether the sentence is true or false. If false, replace the underlined term to make a true sentence.

Mathematics
1 answer:
lara [203]1 year ago
3 0

False , Combining a coin toss and a roll of a die makes a simple event.

In statistics, what does a probability mean?

  • The probability serves as a gauge for how likely an event is to occur. It gauges how likely an event is.
  • P(E) = Number of Favorable Outcomes/Number of Total Outcomes is the formula for probability.
  • Mathematics' study of random events is known as probability, and there are four primary types of probability: axiomatic, classical, empirical, and subjective.
  • Since probability is the same as possibility, you could say that it is the likelihood that a specific event will occur.

False , Combining a coin toss and a roll of a die makes a simple event.

A true statement is​ "For data at the interval​ level, you CAN calculate meaningful differences between data​ entries."

Learn more about probability

brainly.com/question/11234923

#SPJ4

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Evaluate the following expression (a + b)^0
elixir [45]

Answer:

So, (a + b)^0=1

Step-by-step explanation:

(a + b)^0

To evaluete this expression we apply exponential property

x^0=1

IF any expression has exponent 0 then the value is 1 always

for example, 3^0 =1

5^0=1

(x+2)^0=1 because exponent is 0

So, (a + b)^0=1

3 0
3 years ago
Read 2 more answers
Wyatt makes and sells rope doormats. He uses 200 feet of rope for each doormat. He wants to make 25 doormats. Which expression s
olga_2 [115]

Answer: See explanation

Step-by-step explanation:

First and foremost, we should not that:

1 yard = 3 feet

We are informed that Wyatt uses 200 feet of rope for each doormat and that he wants to make 25 doormats.

The expression that shows a correct way to find how many yards of rope he needs will be:

= (200 × 25) / 3

= 5000/3

= 1666.67 yards

4 0
2 years ago
What is the second step in sketching the graph of a rational function?
Elodia [21]

Answer:

C. Choosing test numbers to the left and right of each of the function's zeros and finding the value of the function at each test number

Step-by-step explanation:

Rational function: In mathematics, the term "rational function" is determined as any specific function that can be described through any "rational fraction", in other words, an algebraic fraction, involving both the denominator and the numerator are considered as polynomials. Therefore, the coefficients of specific polynomials are ought not to be in rational numbers and can be considered in the K field.

In the question above, the given statement represents option C is correct.

3 0
3 years ago
I don’t know how to do this
mixas84 [53]

Answer:

Step-by-step explanation:

The first box should be 20.

The second box should be 40

The third box should be .2

The fourth box should be .6

3 0
3 years ago
If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?
Alisiya [41]
If k is odd, then

\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor

while if k is even, then the sum would be

\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4

The latter case is easier to solve:

\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0

which means k=6.

In the odd case, instead of considering the above equation we can consider the partial sums. If k is odd, then the sum of the even integers between 1 and k would be

S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)

Now consider the partial sum up to the second-to-last term,

S^*=2+4+6+\cdots+(k-5)+(k-3)

Subtracting this from the previous partial sum, we have

S-S^*=k-1

We're given that the sums must add to 2k, which means

S=2k
S^*=2(k-2)

But taking the differences now yields

S-S^*=2k-2(k-2)=4

and there is only one k for which k-1=4; namely, k=5. However, the sum of the even integers between 1 and 5 is 2+4=6, whereas 2k=10\neq6. So there are no solutions to this over the odd integers.
5 0
3 years ago
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