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il63 [147K]
3 years ago
13

What is the radius, in centimeters, of a circle that has a circumference of 161 centimeters?

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

25.63694268 = r

Step-by-step explanation:

The circumference is

C = 2*pi*r

161 = 2*(3.14) *r

161 = 6.28 r

Divide each side by 6.28

161/6.28 = r

25.63694268 = r

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17/30 or .56 is your correct answer
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What form is this equation written in? y-7=2(x-6)
Alexxx [7]

Answer:

this is written in point slope form

Step-by-step explanation:

y-y1 = m(x-x1)

the slope is 2

and the point is (6,7)

7 0
3 years ago
Which answer represents a proportional relationship?
allsm [11]
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3 0
3 years ago
Help plzz I don't understand this at all.
Zolol [24]
6.4/8 = y/6 = x/7

0.8/1 = 4.8/6 = 5.6/7

6.4/8 = 4.8/6 = 5.6/7

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I think that’s how you do it but not 100% sure
3 0
3 years ago
Nina and Jo both ran an 8 km race. Nina took 55 minutes to run the whole race. Jo started the race 3 minutes later than Nina but
grin007 [14]

Answer:

Step-by-step explanation:

First we figure out how fast Nina can run. If Nina can run 8 km in 55 minutes, then her rate is

\frac{8km}{55min}=.145\frac{km}{min} and we can use that in a d = rt table:

                 d        =        r        *        t

Nina                            .145

Jo

Now we can fill in the distance which is 6 for both, since that is the distance where they met:

                d        =        r       *        t

Nina         6        =     .145

Jo             6        =

Now we go to the info given about the time. If Jo started the race 3 minutes after Nina, that means that Nina is running 3 minutes longer than Jo. Filling in the time info:

                d        =        r        *        t

Nina          6       =       .145    *      t + 3

Jo              6       =         r       *         t

As you can see, right now we have 2 unknowns in Jo's row. But we don't have to! We will go to Nina's row where the only unknown is time and solve for t. If d = rt, then

6 = .145(t + 3) and

6 = .145t + .435 and

5.55 = .145t so

t = 38.379 minutes. This means that Jo was running 38.379 minutes when she caught up to Nina (it took Nina 3 minutes longer than that to go 6 km since she was already running for 3 minutes when Jo started the race). If Jo's time is 38.379, we can use that in her row for t and solve for r. If d = rt, then

6 = r(38.379) and

r = .16 km/min

Let's check it without the rounding (rounding takes away from the accuracy). If 6 = .145(t + 3) and Nina's rate not rounded is .145454545 and t = 38.37931034, then, rewriting without rounding:

6 should equal .145454545( 38.37931034 + 3)

6 ?=? .145454545(41.37931034)

6 ?=? 6.0 so

Jo's rate is .16 km/min rounded

6 0
3 years ago
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