Herald company had sales of $135,000, sales discounts of $2,000 and sales returns of $3,200. herald company's net sales equals

Applications with Decimals

tresset_1 [31]

$Fraction = \frac{36}{48}$

$Decimal = 0.75$

$Percent = 75 \%$

<em><u>Solution:</u></em>

Given that,

36 rainy days out of 48 days

<h3><u>Find the fraction:</u></h3>

numerator = 36

denominator = 48

Therefore,

$Fraction = \frac{36}{48}$

<h3><u>Decimal:</u></h3>

Convert the fraction to decimal:

$Decimal = \frac{36}{48} = 0.75$

<h3><u>Percent:</u></h3>

We have to find the percent pf 36 rainy days out of 48 days

$Percent = \frac{36}{48} \times 100\\\\Percent = 0.75 \times 100\\\\Percent = 75 \%$

Thus percent is 75 %

7 0

3 years ago

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

3 years ago

What is the average of all interfere from 11 to 35

diamong [38]

Answer:

I'm not so sure what you mean from your question but if we discussed the Average of 11 and 35( positive integers), we would say that it's 23<u>.</u>

8 0

2 years ago

I need help solving this problem

Elena L [17]

Use the given values in the compound interest formula to solve for time, n.

A is the final amount of money, $2800
P is the initial or starting amount $1900
i is the interest rate as a decimal 0.025
n is time in years since it annual.

2800 = 1900(1 + 0.025)^n

2800 = 1900(1.025)^n

2800/1900 = (1.025)^n

28/19 = (1.025)^n

take the natural log of both sides to solve for exponent.

ln(28/19) = ln(1.025^n)

power rule of logarithmic moves exponent

ln(28/19) = n*ln(1.025)

ln(28/19) / ln(1.025) = n

put into a calculator

15.7 years = n

4 0

3 years ago

Yolanda finished 3/4of 10 1/2mile race how many mile sdid she complete

Mila [183]

Answer:

She completed 7.5 3/8 miles of the race.

Step-by-step explanation:

This can be solved with multiplication.

10 * 3/4 = 7.5

1/2 * 3/4 = 1 * 3/2 * 4 = 3/8

7 0

3 years ago