<h3>Given</h3>
<h3>Find</h3>
<h3>Solution</h3>
It can be convenient to rewrite f(x) as a square, then do the substitution. That way, the algebra is simplified a little bit.
... f(x) = (x +1)²
... f((2a-3)/5) = ((2a-3)/5 +1)² = ((2a -3 +5)/5)²
... = (2/5(a+1))²
... f((2a-3)/5) = (4/25)(a² +2a +1)
Answer:
Ayush's route is 0.7 km or 700m longer than Sumit route.
Step-by-step explanation:
Ayush's route is 1km 2hm long while sumit route is 2hm 30dam.
We know that,
1 km = 10 hm
1 dam = 0.1 hm
Using these conversions we get
Ayush's route = 1km 2hm = (1×10) hm + 2 hm = 12 hm
Sumit route = 2hm 30dam = 2 hm + (30×0.1) hm = 2 hm + 3 hm = 5 hm
Ayush's route is longer.
Difference = 12 hm - 5 hm = 7 hm = 0.7 km [1 km = 10 hm]
Hence, Ayush's route is 0.7 km or 700 m longer than Sumit route.
Answer:
Option A. √(x + 1)
Step-by-step explanation:
Data obtained from the question include:
f(x) = √(x² – 1)
g(x) = √(x – 1)
(f/g) (x) =..?
(x² – 1) => difference of two square
(x² – 1) => (x – 1)(x + 1)
f(x) = √(x² – 1)
f(x) = √(x – 1)(x + 1)
(f/g) (x) = f(x) /g(x)
f(x) = √(x – 1)(x + 1)
g(x) = √(x – 1)
(f/g) (x) = √(x – 1)(x + 1) / √(x – 1)
(f/g) (x) = √[(x – 1)(x + 1) / (x – 1)]
(f/g) (x) = √(x + 1)
Answer:
Whole numbers are also integers. There are other integers which are the opposites of the whole numbers (−1, −2, −3, ...). These negative numbers lie to the left of 0 on the number line. Integers are the whole numbers and their opposites.
32-x=0; with x equaling the amount descended or -32.
