Question

A company logo is shaped like an equilateral triangle with 2-in.-long sides. What is the height of the logo? Round to the nearest tenth. A. 1.0 in. B. 1.7 in. C. 2.0 in. D. 1.4 in.

Answer 1

Answer:

B. 1.7 in

Step-by-step explanation:

Divide the triangle into 2 congruent right angle triangles

With hypotenuse: 2

Base: 2/2 = 1

Using pythagoras theorem

2² = 1² + h²

h² = 3

h = sqrt(3)

h = 1.732050808

Answer 2

Step-by-step explanation:

Step 1:  Make two same right triangles

If we split the equilateral triangle in half, that will give us a hypotenuse of 2 and a leg that is 1.  Use the Pythagorean Theorem to find the height/second leg.

$(1)^2 + b^2 = (2)^2$

$1 + b^2 = 4$

$b^2 = 3$

$b = \sqrt{3}$

$b = 1.732...$

Answer:  Option B, 1.7 in