Answer:
The Solution of the equation is
x= 5 ±
Step-by-step explanation:
We are supposed to find the solution of the equation by completing square method
our given equation is
2x² + 20x + 10 = 0
Dividing whole equation by 2
we will get
x² + 10 x + 5 = 0
Now we will write the middle term in factor form to see what we will be needing to make it perfect square
it would be written as
x² + 2(5) x + 5 = 0
Now adding 20 on both sides we get
x² + 2(5) x + 5 + 20 = 20
x² + 2(5) x + 25 = 20
(x)² + 2(5) x +(5)² = 20
Now we have the form of a²+2(a)(b) + b²
And also we know that
a²+2(a)(b) + b² = (a+b)²
So our equation becomes
(x+5)² = 20
Taking square root of both sides it becomes
square cuts out with square root so
it becomes
x+5 = ±
We know that
So it becomes
x+5 =±
Subtracting 5 from both sides
it becomes
x= 5 ±
So
The Solution of the equation is
x= 5 ±
Answer:
Y=cd-ax/b
Step-by-step explanation:
You r to use change of subject of the dormula
Answer:
I’m not 100% sure but I think 120°.
Step-by-step explanation:
This is because, angles on a straight line add up to 180°. Because there is 60 degrees on one side of line B, this means the other section is 120° (120°+60°=180°) The angle labelled (3x) is alternate to the angle of 120°. Alternate angles are always equal, meaning that 3x is equal to 120°.
I hope this is right.
Answer: (x,y) = (7,-3)
Step-by-step explanation:
-4x - 10y = 2.........(1)
-6x - 10y = -12.........(2)
Subtract (2) from (1)
-4x — (-6x) -10y — (-10y) = 2 — (-12)
-4x + 6x + 0 = 2 + 12
2x = 14
x = 14/2
x = 7.
Substitute 7 for x in (1)
-4(7) - 10y = 2
-28 — 10y = 2
-10y = 2 + 28
-10y = 30
y = 30/-10
y = -3.
(x,y) = (7,-3)
Hope this helps?
Given:
m∠APB = 19°
To find:
The arc measure of DBC.
Solution:
∠APB and ∠DPC are vertical angles.
By vertical angle theorem:
m∠APB = m∠DPC
m∠DPC = 19°
DB is the diameter of the circle.
Angle measure of diameter = 180°
m∠DPB = 180°
m∠DPC + m∠CPB = m∠DPB
19° + m∠CPB = 180°
Subtract 19° from both sides.
19° + m∠CPB - 19° = 180° - 19°
m∠CPB = 161°
<em>The measure of central angle is equal to the measure of intercepted arc.</em>
m∠CPB = m(ar CPB)
m(ar CPB) = 161°
The arc measure of DBC is 161°.