Question

The distance a free falling object had traveled can be modeled by the equation d=1/2 at^2 where a is acceleration due to gravity and t is the amount of time the object has fallen. What is t in terms of a and d?

Answer 1

Answer:

Answer:

 t = √(2d/a)

Step-by-step explanation:

To solve for a variable, undo the operations done to that variable, in reverse order. Here, t is squared, then multiplied by a/2.

 d = (a/2)t^2

Multiply by 2/a.

 2d/a = t^2

Take the square root.

 t = √(2d/a)

Answer 2

D=(1/2)*a*t²
Multiply both sides by 2
2d= a*t²

Divide both sides by a
2d/a=t²

Now take square root both sides. You will get t in terms of d and a