3 years ago

D(5, 7), E(4, 3), and F(8, 2) form the vertices of a triangle. What is m∠DEF? A. 30° B. 45° C. 60° D. 90°

Mathematics

1 answer:

viva [34]3 years ago

4 0

D hope this helps man

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Simplify:$$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}$$

bagirrra123 [75]

Answer:

$5\sqrt{3}$

Step-by-step explanation:

$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}=?\\\\1)\sqrt{8^2+15^2}=\sqrt{289}=17\\2)\sqrt{9^2+40^2}=\sqrt{1681}=41\\3)2\times17=34\\4)\sqrt{34+41}=5\sqrt{3}$

All Done!

8 0

3 years ago

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The measure of 2WXZ is 100°.<br> What is the measure of ZYXZ?

Rom4ik [11]

Answer:

a) 69.99

b) .20%

Your welcom ,.hb

Step-by-step explanation:

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3 years ago

Find the value of k if the distance between (2,k) and (6,7) is 4√2 unit

andreyandreev [35.5K]

Answer:

k = 3

Step-by-step explanation:

We have the distance formula: $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ . We can plug in $4\sqrt{2}$ = d, x2 = 6, x1=2, y2 = 7, y1 = k.

Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

$4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\$

$(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2$

$32 = (4)^2 + (7-k)^2$

$32 = 16 + (7-k)^2$

$32 - 16 = (7-k)^2$

$16 = (7-k)^2$

$\sqrt{16} = (7-k)$

$4 = 7-k$

$k = 3$

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3 years ago

The solution to 5 - 3x> 35 is either x>-10 or -10> x. which solution is correct

velikii [3]

It should be x < -10 because when you divide by a negative number the inequality sign flips.

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3 years ago

1436cm =?m how many meters

swat32

To get cm to meters you must divide by 100! 1436 / 100 = 143.60 m

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3 years ago

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