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mrs_skeptik [129]
3 years ago
15

If the translation T maps point A(-3,1) onto point A'(5,5), what is he translation T?

Mathematics
2 answers:
monitta3 years ago
8 0
<h2>Answer:</h2>

The translation T is given by:

                        T(x,y)=(x+8,y+4)

i.e. it shifts the point 8 units to the right and 4 units up.

<h2>Step-by-step explanation:</h2>

The translation is the transformation that changes the location of points of the figure but there is no change in the shape as well as size of the original figure.

It is given that:

The translation T maps point A(-3,1) onto point A'(5,5).

so, if the translation rule that is used is:

(x,y) → (x+h,y+k)

Here

(-3,1) → (5,5)

i.e.

-3+h=5    and  1+k=5

i.e.

h=5+3   and   k=5-1

i.e.

h=8   and   k=4

Hence, the translation is 8 units to the right and 4 units up.

-Dominant- [34]3 years ago
5 0

Answer:

< 8, 4 >

Step-by-step explanation:

Consider the coordinates

x- coordinate A - 3 → A' 5 → that is + 8

y- coordinate A 1 → A' 5 → that is + 4

Hence T = < 8, 4 >

or (x, y) → (x + 8, y + 4)

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Step-by-step explanation:

Given that:

The scientific notation = 10⁻¹⁰

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Let say 10⁻¹ will be \dfrac{1}{10} in scientific notation;

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Now; we are given 10⁻¹⁰ as a scientific notation,

To standard notation, we get:

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A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri
GuDViN [60]

Answer:

1.\frac{dy}{dt}=ky

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

\frac{dy}{dt}=Number of bacteria per unit time

\frac{dy}{dt}\proportional y

\frac{dy}{dt}=ky

Where k=Proportionality constant

2.\frac{dy}{y}=kdt,y'(0)=100

Integrating on both sides then, we get

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We have y(0)=200

Substitute the values then , we get

ln 200=k(0)+C

C=ln 200

Substitute the value of C then we get

ln y=kt+ln 200

ln y-ln200=kt

ln\frac{y}{200}=kt

\frac{y}{200}=e^{kt}

y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

Substitute the given condition then, we get

100=200ke^{0}=200 \;because \;e^0=1

k=\frac{100}{200}=\frac{1}{2}

y=200e^{\frac{t}{2}}

Substitute t=2

Then, we get y=200e^{\frac{2}{2}}=200e

y=200(2.718)=543.6=543.6

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0
4 years ago
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