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7nadin3 [17]
3 years ago
7

What are two different ways of factoring -3x - 9? Select all that apply ​

Mathematics
1 answer:
andrew11 [14]3 years ago
4 0

Answer:

-3x - 9 can be factored as -3(x + 3)

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What is c=2(3.14)r solve for r
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C=<span>6.28<span>r let me know if you need more help</span></span>
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You have $100,000 to get some medical supplies for your clinic. Write an expression that represents the total cost if you decide
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(3t+100k+3m+250a)

   

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PLS HELP ASAP Cherries cost d dollars per pound. Mother bought 3 lbs and father bought 2 lbs. How much money did they spend toge
julia-pushkina [17]

Answer:

5d

Step-by-step explanation:

Mother: 3d

Father: 2d

Total: 3d + 2d = 5d

8 0
3 years ago
Point P is located at (-2, 7), and point R is located at (1, 0). find the y value for the point Q that is located 2/3 the distan
Dominik [7]

Just did this one.

Answer: 7/3 or about 2.3, choice (d).



Step-by-step explanation:


R-P= (3,-7). the displacement vector.


P+x(R-P) moves to x times distance between


P+(R-P) = R moves to 100% of the distance.


Q = P+2/3(R-P)


= (-2,7)+2/3(3,-7)


= (-2,7)+(2,-14/3)


= (0,7-14/3)


= (0,7/3)


= (0,2.3333...)


Read more on Brainly.com - brainly.com/question/11869584#readmore

7 0
3 years ago
A technician is installing two bundles of cables for an online system. Bundle A is 1
Mila [183]

Answer:

Answer D: 8.7 cm

Step-by-step explanation:

First compare the actual diameters of both cables to find out which one is larger. If we write both diameters in fraction form (as they are given), we need to have them expressed with the same denominator for a straight forward comparison:

Bundle A: 1\frac{3}{8} =1+\frac{3}{8} = \frac{8}{8} +\frac{3}{8} =\frac{11}{8}

Bundle B: 2\frac{3}{4} =2+\frac{3}{4}=\frac{8}{4} +\frac{3}{4}=\frac{11}{4}

So we multiply this last fraction by 2 in numerator and denominator to obtain the same denominator as for Bundle A without actually changing its numerical value: \frac{11}{4} = \frac{22}{8}

So now we compare Bundle A with bundle B, and see that bundle B has the larger diameter: 22/8 inches

The hole has to be 25% larger than this larger diameter, so we estimate 25% of 22/8 in is:

\frac{22}{8} * \frac{25}{100} = 0.6875 inches

Therefore, the hole must be of diameter 22/8 in plus 0.6875 in = 3.4375 in

Now we convert this value into centimeters by multiplying it by 2.54 (since one inch is 2.54 cm):

3.4375 * 2.54 = 8.73125 cm

which rounded to the nearest tenth as requested in the problem is: 8.7 cm

8 0
4 years ago
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