The volume of a rectangular prism is represented by the following equation:
![V=w*h*l](https://tex.z-dn.net/?f=V%3Dw%2Ah%2Al)
Where the variables are for volume, width, height, and length, respectively.
We are given that the area of one end is 16 cm² (units have to be correct when solving these problems, so it's 16 cm², not 16 cm as described in the problem). We know that ![A=w*h](https://tex.z-dn.net/?f=A%3Dw%2Ah)
Using this knowledge, we can change the volume equation to our needs.
![V=w*h*l](https://tex.z-dn.net/?f=V%3Dw%2Ah%2Al)
![V=(w*h)*l](https://tex.z-dn.net/?f=V%3D%28w%2Ah%29%2Al)
![V=A*l](https://tex.z-dn.net/?f=V%3DA%2Al)
Note: We know that A is 16 since it's given
![V=16*l](https://tex.z-dn.net/?f=V%3D16%2Al)
The volume is 208 cm³ (once again, incorrect units given). Insert this into the equation.
![208=16*l](https://tex.z-dn.net/?f=208%3D16%2Al)
Divide both sides of the equation by 16.
![13=l](https://tex.z-dn.net/?f=13%3Dl)
The length is 13 cm.
Let me know if you need any clarifications, thanks!
The answer to 89+27+11 is 127
The correct question is
<span>Given cos theta=4/9 and csc theta < 0 find sin theta and tan theta
</span>
we know that
csc theta=1/sin theta
if csc theta < 0
then
sin theta < 0
we have that
<span>cos theta=4/9
we know that
sin</span>² theta+cos² theta=1
so
sin² theta=1-cos² theta-----> 1-(4/9)²----> 1-(16/81)----> 65/81
sin theta=-√(65/81)---->-√65/9
the answer Part a) is
sin theta=-√65/9
Part b) find tan theta
tan theta=sin theta/cos theta
tan theta=(-√65/9)/(4/9)-----> tan theta=-√65/4
the answer part b) is
tan theta=-√65/4
The answer is 4x-6. Good luck! :D
Answer: 5/4
Step-by-step explanation:
if two number have the same denominator, then the number with the greatest numerator is the greatest.
Basically if the bottom number of two fractions are the same, the bigger top number is the bigger number.