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melisa1 [442]
3 years ago
13

Point P is located at (-2, 7), and point R is located at (1, 0). find the y value for the point Q that is located 2/3 the distan

ce from point P to point R.
a. 4.9


b. 4.7


c. 2.5


d. 2.3
Mathematics
1 answer:
Dominik [7]3 years ago
7 0

Just did this one.

Answer: 7/3 or about 2.3, choice (d).



Step-by-step explanation:


R-P= (3,-7). the displacement vector.


P+x(R-P) moves to x times distance between


P+(R-P) = R moves to 100% of the distance.


Q = P+2/3(R-P)


= (-2,7)+2/3(3,-7)


= (-2,7)+(2,-14/3)


= (0,7-14/3)


= (0,7/3)


= (0,2.3333...)


Read more on Brainly.com - brainly.com/question/11869584#readmore

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Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
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Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

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