Let us use the formula with the point (4,5) and (0,2)
![\begin{gathered} d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}=\sqrt[]{(4-0)^2+(5-2)^2} \\ =\sqrt[]{16+9}=\sqrt[]{25}=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%3D%5Csqrt%5B%5D%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D%3D%5Csqrt%5B%5D%7B%284-0%29%5E2%2B%285-2%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B16%2B9%7D%3D%5Csqrt%5B%5D%7B25%7D%3D5%20%5Cend%7Bgathered%7D)
Answer:
(x^2 + 3)(x + 1).
Step-by-step explanation:
x^3 + x^2 + 3x + 3
= x^2(x + 1) + 3(x + 1)
= (x^2 + 3)(x + 1).
Answer: C. x-2
Step-by-step explanation:
We have the following expression:
Factoring in the numerator:
Factoring again in the numerator with common factor 
:
Simplifying:
Hence, the correct option is C. x-2
Answer:
x=6
Step-by-step explanation:
We can write this as a ratio
x 9
---- = --------
10 15
Using cross products
15x = 10*9
15x = 90
Divide by 15
15x/15 = 90/15
x =6
You probably are interested in expressing the given equation as a quadratic equation in u, as it will make it easy to find the solutions.
Let u = x²
So,
u² = x⁴
So, the given equation can be written as:
u² - 17u + 16 = 0
Now the equation is quadratic in u and the solutions can be calculated using quadratic formula or factorization.
