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vovikov84 [41]
3 years ago
13

I need help fast geometry is impossible

Mathematics
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

  • D. 8

Step-by-step explanation:

  • DC = AC = x is the radius

<u>Using the Pythagorean theorem, find x:</u>

  • (x + 9)² - x² = 15²
  • x² + 18x + 81 - x² = 225
  • 18x = 225 - 81
  • 18x = 144
  • x = 144/18
  • x = 8
Vikki [24]3 years ago
6 0

Answer:x = 8

Step-by-step explanation:

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Write the equation of a line, in slope-intercept form, that has a slope of m=9 and passes through the point (4, 31)
Darina [25.2K]

Answer:

9x-y = 5

Step-by-step explanation:

Equation of line in slope intercept form:

y-y1 = m*(x-x1), m=9, (x1,y1)=(4,31)

y-31 = 9*(x-4)

y-31 = 9x-36

9x-y = 36-31

9x-y = 5

4 0
3 years ago
2
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Answer:

C

Step-by-step explanation:

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3 years ago
Is there any video related to this or can you explain how to do it
uranmaximum [27]

Angles ECD  and CEF add to 180

40+140 = 180

So that means we have EF parallel to CD (due to the same side interior angle theorem)

--------------

Angles BCE and ECD combine to 30+40 = 70, which is congruent to angle ABC = 70 as well.

In other words, this shows angle ABC = angle BCD. Both of these angles are alternate interior angles. Since they're congruent, they lead to AB being parallel to CD.

--------------

So far we have

AB || CD

CD || EF

Using the transitive property, we can then link the two statements to say AB || EF. Think of a chain where CD is the common link. We go from AB to CD, then from CD to EF. So we can just take a single path from AB to EF.

It's like saying "P --> Q and Q --> R, therefore P --> R"

4 0
3 years ago
Pic attached<br> solve for x
nordsb [41]
The answer to your question is  x = -3

6 0
3 years ago
Read 2 more answers
Using the TI-84 calculator, find the area under the standard normal curve. Round the answers to four decimal places.(a) Find the
madam [21]

Answer:

a) 0.705

b) 0.976

c) 0.01

d) 0.09

Step-by-step explanation:

We have to find the area under the standard normal curve.

a) area under the standard normal curve that lies outside the interval between z= −1.98 and z=0.61.

=P(-1.98

b) area under the standard normal curve to the left of z=1.98

=P(z

c) area under the standard normal curve to the right of z= 2.34

P(z>2.34)\\=1 - P(z

d)  area under the standard normal curve that lies between z= −0.94 and z= −0.63

=P(-0.94

6 0
3 years ago
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