The probability that first a red bead is drawn and next a blue bead is drawn is 7/30,and both events are dependent
<h3>How to determine the probability?</h3>
The distribution of the beads are:
Red = 3
Blue = 7
Total = 10
The probability of selecting the red bead first is:
P(Red) = 3/10
When the red bead is selected, the number of beads becomes 9
So, the probability of selecting a blue bead is
P(Blue) = 7/9
The probability of the event is then calculated using:
P = 3/10 * 7/9
Evaluate
P = 7/30
Hence, the probability of the event is 7/30
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Answer:
1.6 = x axis || 2.5 = y axis
Step-by-step explanation:
each line is 0.5
Step-by-step explanation:
y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1
dy/dx = 12√x
Arc length is:
s = ∫ ds
s = ∫₀¹ √(1 + (dy/dx)²) dx
s = ∫₀¹ √(1 + (12√x)²) dx
s = ∫₀¹ √(1 + 144x) dx
If u = 1 + 144x, then du = 144 dx.
s = 1/144 ∫ √u du
s = 1/144 (⅔ u^(³/₂))
s = 1/216 u^(³/₂)
Substitute back:
s = 1/216 (1 + 144x)^(³/₂)
Evaluate between x=0 and x=1.
s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]
s = 1/216 (145)^(³/₂) − 1/216
s = (145√145 − 1) / 216
Step-by-step explanation:
700.50√315=2.65
2.65×1.50=
