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jekas [21]
3 years ago
14

8a+5b+3abc when a = 1, b= 2 and c= 3

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

8*1+5*2+3*1*2*3

8+10+18

36 is the answer

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Solve the initial value problem yy′+x=x2+y2‾‾‾‾‾‾‾√ with y(1)=8‾√. To solve this, we should use the substitution u= x^2+y^2 help
leva [86]

Looks like the equation is

yy'+x=\sqrt{x^2+y^2}

Substitute u(x)=x^2+y(x)^2, so that u'=2x+2yy'. Then the equation is the same as

\dfrac{u'-2x}2+x=\sqrt u\implies u'=2\sqrt u\implies\dfrac{\mathrm du}{2\sqrt u}=\mathrm dx

Integrate both sides to get

\sqrt u=C\implies\sqrt{x^2+y^2}=C

Given that y(1)=\sqrt8, we have

\sqrt{1^2+(\sqrt8)^2}=C\implies C=3

so the solution is

\sqrt{x^2+y^2}=3

7 0
3 years ago
Which of the following equations could be used to determine the value of X
Tcecarenko [31]

Answer:

D

Step-by-step explanation:

If the original price is x and you deduct 3, you'l have x - 3.

If you buy 4 of them, you multiply that price by 4, giving you 4(x - 3).

Then, if that value is equal to 27, you get 4(x - 3) = 27

5 0
3 years ago
Read 2 more answers
How many solutions are there to the equation below?<br> 6x + 33 = 6(x+6)
Ainat [17]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Let's solve ~

  • 6x + 33 = 6(x + 6)

  • 6x + 33 = 6x + 36

Here, 6x is present on both the sides of equation so they cancel out ~ therefore there is no one solution satisfying the equation ~

3 0
3 years ago
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A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes
hammer [34]

Answer:

a) The probability that this whole shipment will be​ accepted is 30%.

b) Many of the shipments with this rate of defective aspirin tablets will be rejected.

Step-by-step explanation:

We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.

We select a sample of size 48 and test for defectives.

If more than one aspirin is defective, the batch is rejected.

The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48

We have to calculate the probabilities that X is equal or less than 1: P(X≤1).

P(X\leq1)=P(X=0)+P(X=1)\\\\\\P(0)=\binom{48}{0}(0.05)^0(0.95)^{48}=1*1*0.0853=0.0853\\\\\\P(1)=\binom{48}{1}(0.05)^1(0.95)^{47}=48*0.05*0.0897=0.2154\\\\\\P(X\eq1)=0.0853+0.2154=0.3007

8 0
4 years ago
A bag contains 70 pencils out of which 15 are green and 30 blue.(i)How many pencils of other colours. are in the bag?(ii)A penci
Bas_tet [7]

Answer:

i) 25

ii) 30:70; 30 out of 70 pencils will be blue.

Step-by-step explanation:

i) 70 - (15+30)= 25 other colors in the bag.

ii) 30:70

4 0
4 years ago
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