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natulia [17]
3 years ago
6

Helpp! Will give brainliest​

Mathematics
1 answer:
babymother [125]3 years ago
3 0

Answer:

all of them are correct

Step-by-step explanation:

You might be interested in
Find the MAD for this set of data
diamong [38]

Using it's concept, it is found that the Mean Absolute Deviation for this set of data is of 0.8.

<h3>What is the mean absolute deviation of a data-set?</h3>

  • The mean of a data-set is given by the sum of all observations divided by the number of observations.
  • The mean absolute deviation of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations. Hence, it is the sum of deviations divided by the number of observations.
  • The mean absolute deviation represents the average by which the values differ from the mean.

In this problem, there are 10 observations, and the sum of the deviations is of 1 + 3 + 1 + 1 + 1 + 1 = 8. Hence the MAD is given as follows:

MAD = 8/10 = 0.8.

More can be learned about the Mean Absolute Deviation at brainly.com/question/3250070

#SPJ1

7 0
3 years ago
if you could pick the same number twice and the first numbers is odd and less than 5, then the probability that the sum of the t
Tems11 [23]
The 1st number is odd, less than 5, so it might be 1 or 3, the probability is 2/10
But if the sum has to less than 5, than *when 1st number is 1, the second number can only be 1.2.3
and *when 1st number is 3, 2nd can only be 1
*1: 3/100
*2: 1/100
3/100+1/100=4/100
so the answer should be (4/100)/(2/10)=2/10=1/5
I'm not so sure if I'm right
plz tell me if there's something wrong with my answer
3 0
4 years ago
18/27=1/3 9/15&lt;4/4 3/4&lt;2/3 5/6&gt;11/12 which is a true statement?
hram777 [196]

Answer:

The correct answer us 9/15<4/4

Can I please have a brainliest? I want to rank up :)

6 0
3 years ago
Write the number 4, 207 in expanded form.
sergiy2304 [10]
The Answer is the first one
5 0
3 years ago
NO LINKS!!!
Ber [7]

Refer to this previous solution set

brainly.com/question/26114608

===========================================================

Problem 4

Like the three earlier problems, we'll place the kicker at the origin and have her kick to the right. The two roots in this case are x = 0 and x = 20 to represent when the ball is on the ground.

This leads to the factors x and x-20 and the equation y = ax(x-20)

We'll plug in (x,y) = (10,28) which is the vertex point. The 10 is the midpoint of 0 and 20 mentioned earlier.

Let's solve for 'a'.

y = ax(x-20)\\\\28 = a*10(10-20)\\\\28 = -100a\\\\a = -\frac{28}{100}\\\\a = -\frac{7}{25}\\\\

This then leads us to:

y = ax(x-20)\\\\y = -\frac{7}{25}x(x-20)\\\\y = -\frac{7}{25}x*x-\frac{7}{25}x*(-20)\\\\y = -\frac{7}{25}x^2+\frac{28}{5}x\\\\

The equation is in the form y = ax^2+bx+c with a = -\frac{7}{25}, \ b = \frac{28}{5}, \ c = 0

The graph is below in blue.

===========================================================

Problem 5

The same set up applies as before.

This time we have the roots x = 0 and x = 100 to lead to the factors x and x-100. We have the equation y = ax(x-100)

We'll use the vertex point (50,12) to find 'a'.

y = ax(x-100)\\\\12 = a*50(50-100)\\\\12 = -2500a\\\\a = -\frac{12}{2500}\\\\a = -\frac{3}{625}\\\\

Then we can find the standard form

y = ax(x-100)\\\\y = -\frac{3}{625}x(x-100)\\\\y = -\frac{3}{625}x*x-\frac{3}{625}x*(-100)\\\\y = -\frac{3}{625}x^2+\frac{12}{25}x\\\\

The graph is below in red.

4 0
3 years ago
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