Answer:
Hope this is right.
1. 7(4x-5)
2. 28x-35
Step-by-step explanation:
Answer:
First we need to name some of the variables we are given:n = 38 the sample sizex = 6.88 the sample mean = 1.86 the population standard deviationWe need to find a 90% confidence interval for the mean price per 100 lbs of watermelon: = 1-.90 = .10/2 = .05z(/2) = -1.64-z(/2) = 1.64This can give us a probability expression:P(-1.645 < z < 1.645) = .90The margin of error is calculated with the formula: E = z(/2)(/√n)E = 1.645(1.86/√38) = $.4963(300) = $148.89 Then to calculate the upper and lower limit we add and subtract E from x:lower limit = 6.88 - .4963 = $7.38(300) = $2214upper limit = 6.88 + .4963 = $6.38(300) = $1914Note: We multiply the E, upper and lower limits by 300 because 15 tons is 30000lbs and we need the price per 100 lbs, so we divide 30000/100 and get 300.
Step-by-step explanation:
Answer:
$4,116
Step-by-step explanation:
Worth of Mike's car at the start of 2014 = $12,000
If the car is said to depreciates every year by 30% = 30/100 = 0.3
The worth of the car at the start of 2017 is what we are to determine.
This means that the car depreciated by 30% (0.3) for 3 years since 2014 (2017 - 2014 = 3 yrs)
The worth at the start of 2017 would be calculated as follows:
12,000 × (1 - 0.3)³
= 12,000 × (0.7)³
= 12,000 × 0.343
= 4,116
Worth of the car at the start of 2017 would be $4,116
Answer:
Blue line: y = -2
Red line: y = 2/3 x + 2
Perpendicular to red line: y = -3/2x + 2
Parallel to red line: y = 2/3 x + any real number
Answer: Graph B
Step-by-step explanation:
The unit price for the strawberries is:
= 1.5 / 2
= $0.75 per pound
Graph B is the right graph as it uses a unit price of $0.75 per pound for strawberry price. This is why it has points of the graph that mirror the friends purchases such as (2, 1.5) , (3, 2.5) and (4, 3).
