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pochemuha
2 years ago
13

Tìm tất cả các giá trị của y sao cho. x2 + y2 +2z2 +2xy - 2xz - 4yz + 3y >= 0 với mọi x, z

Mathematics
1 answer:
Ksju [112]2 years ago
4 0

Answer:

shimani mashashina mashina shishushi mashinana

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You buy rice at $0.71 a pound. One batch of fried rice requires 3 pounds rice. How much does the rice for one batch cost? Round
Phoenix [80]

Answer:

To make one batch of fried rice you'd need to pay $2.13

Step-by-step explanation:


4 0
2 years ago
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Write the sentence as an inequality. Then solve the inequality.
Alex777 [14]
I only know the part 3*n-8≤ -7
4 0
2 years ago
Answer 10 only please, explain how you got your answer
ira [324]

Question:

The circumference of a clock is 22 inches. What is the radius of the clock?

Answer:

Radius = 3.5 inches

Solution:

Shape of the clock is circle.

Circumference of the circle = 2πr

Circumference of a clock = 22 inches

\Rightarrow2\pi r=22

$\Rightarrow2\times\frac{22}{7}\times  r=22

$\Rightarrow\frac{44}{7}\times  r=22

$\Rightarrow  r=22\times \frac{7}{44}

$\Rightarrow  r=\frac{7}{2}

⇒ r = 3.5 inches

Hence the radius of the clock is 3.5 inches.

8 0
3 years ago
|9x-7|=|6x+3| Solve the inequality
dexar [7]

Answer:

x = 4/15 and x= 10/3

Step-by-step explanation:

|9x-7|=|6x+3|

There are two solutions, one positive and one negative.

(9x-7)=6x+3                   - (9x-7)=6x+3

We will take the positive one first

(9x-7)=6x+3

Subtract 6x from each side

(9x-6x-7)=6x-6x+3

3x -7=3

Add 7 to each side

3x-7+7 = 3+7

3x = 10

Divide by 3x/3 = 10/3

x = 10/3


Now we will take the negative solution

- (9x-7)=6x+3

Distribute the negative sign

-9x+7 = 6x+3

Add 9x to each side

-9x+9x+7 = 6x+9x+3

7 = 15x+3

Subtract 3 from each side

7-3 = 15x +3-3

4 = 15x

Divide by 15 on each side

4/15 =15x/15

4/15 =x

8 0
3 years ago
Can anyone help me out with these two problems please? Thanks!
V125BC [204]
1) x = 60/31 = 1.935
2.) m = 8/3 = 2.667
So if you go on tiger algebra, they will show the steps taken to get there. Hope this helps!
8 0
3 years ago
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