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nordsb [41]
3 years ago
10

Let f(x)=x-2 and g(x)=x2-7x-9 find f(g(-1))

Mathematics
2 answers:
Reptile [31]3 years ago
8 0

g(-1) =  (-1)^2 - 7(-1) - 9

= 1 + 7 - 9 =  -1

f(g(-1)  =  (-1) - 2 = -3 (answer)

ira [324]3 years ago
3 0
....................

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A stool of ribbon holds 6.75 meters.A craft club buys 21 stools. What is the total cost if the ribbon sells for $2 per meter.
OLEGan [10]

283.5

So you multiply 6.75 by 21 stools to find the total number of meters. Then you multiply that by 2.

7 0
3 years ago
Answer all 4 please
FrozenT [24]
1)
180 - (37 + 90) = 180 - 127 \\ = 53
2)
(180 - 15) \div 2 = 165 \div 2 \\ = 82.5
each of other angles measures 82.5 degrees

3)
180 - (42 + 20) = 180 - 62 \\ = 118
4)sorry I don't know the last one
7 0
3 years ago
Round 4802 to the lead digit
Lelechka [254]

Answer:

It would be 5000

Step-by-step explanation:

It would be 500 b/c the number is a greater number that is 4802 and it is closer to 5000 than 4000

8 0
3 years ago
A helicopter is flying above a town. the local high school is directly to the east of the helicopter at a 20° angle of depressio
guapka [62]
Answer: 4.5 miles

Explanation:

When you draw the situation you find two triangles.

1) Triangle to the east of the helicopter

a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°

b) hypotensue = distance between the high school and the helicopter

c) opposite-leg to angle 20° = heigth of the helicopter

d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x

2) triangle to the west of the helicopter

a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°

b)  distance between the helicopter and the elementary school = hypotenuse

c) opposite-leg to angle 62° = height of the helicopter

d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x

3) tangent ratios

a) triangle with the helicpoter and the high school

tan 20° = Height / x ⇒ height = x tan 20°

b) triangle with the helicopter and the elementary school

tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°

c) equal the height from both triangles:

x tan 20° = (5 - x) tan 62°

x tan 20° = 5 tan 62° - x tan 62°

x tan 20° + x tan 62° = 5 tan 62°

x  (tan 20° + tan 62°) = 5 tan 62°

⇒ x = 5 tant 62° / ( tan 20° + tan 62°)

⇒ x = 4,19 miles

=> height = x tan 20° = 4,19 tan 20° = 1,525 miles

4) Calculate the hypotenuse of this triangle:

hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²

hipotenuse = 4.46 miles

Rounded to the nearest tenth = 4.5 miles

That is the distance between the helicopter and the high school.
5 0
3 years ago
Read 2 more answers
A distribution with µ = 55 and σ = 6 is being standardized so that the new mean and standard deviation will be µ = 50 and σ = 10
Alekssandra [29.7K]

Solution:

\hbox{Let the distribution standarized is z}\\ \hbox{given:-}\mu =50\hbox{ and} \sigma =6\hbox{will become } \mu=50 \hbox{ and} \sigma =10\\\hbox{distribution standarized with value x=52 }\\\rm{so}\\\hbox{the value of score is:}\\z=\frac{x-\mu }{\sigma}\\\rm{if}\\p(x< 52)=p(z

3 0
2 years ago
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