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Lunna [17]
2 years ago
14

Need help please and thank you

Mathematics
1 answer:
agasfer [191]2 years ago
6 0

Answer:

Could you take a screenshot this image is quite blurry and I can't see any values and hardly the line. This is not gonna be able to be answered until you fix this.

Step-by-step explanation:

Fix image and I will answer again

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the length of a rectanglr exceeds its width by 5 inches, and the area is 84 square inches. what are the length and width of a a
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The area is the product of length and width, which is to say that the length and width are factors of the area.

Assuming the dimensions are integers, you want factors of 84 that differ by 5.

... 84 = 1×84 = 2×42 = 3×28 = 4×21 = 6×14 = 7×12

The last of these pairs differ by 5, so ...

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4 years ago
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Please help me asap<br>​
Lera25 [3.4K]

Answer:

Step-by-step explanation:

From the picture attached,

∠4 = 45°, ∠5 = 135° and ∠10 = ∠11

Part A

∠1 = ∠4 = 45°  [Vertically opposite angles]

∠1 + ∠3 = 180° [Linear pair of angles]

∠3 = 180° - ∠1

     = 180° - 45°

     = 135°

∠2 = ∠3 = 135°  [Vertically opposite angles]

∠8 = ∠5 = 135° [Vertically opposite angles]

∠5 + ∠6 = 180° [Linear pair of angles]

∠6 = 180° - 135°

∠6 = 45°

∠7 = ∠6 = 45° [Vertically opposite angles]

By triangle sum theorem,

m∠4 + m∠7 + m∠10 = 180°

45° + 45° + m∠10 = 180°

m∠10 = 180° - 90°

m∠10 = 90°

m∠10 = m∠12 = 90°  [Vertically opposite angles]

m∠10 = m∠11 = 90° [Given]

Part B

1). ∠1 ≅ ∠4  [Vertically opposite angles]

2). ∠7 + ∠5 = 180° [Linear pair]

3). ∠9 + ∠10 = 180° [Linear pair]

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Answer:

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