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Katen [24]
2 years ago
11

Find angle M and angle J of the isosceles trapezoid

Mathematics
1 answer:
fgiga [73]2 years ago
3 0
Angle J would be 118 degrees and angle M would be 62 degrees. this is because it’s an isosceles trapezoid and corresponding angles are the same.
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Which points are solutions to the system of inequalities? Select ALL that apply.
ZanzabumX [31]

Answer:

0,0

2,-1

-2,4

Step-by-step explanation:

3 0
3 years ago
Find the two angles and show work!!!
USPshnik [31]

Answer:

x=23.5

Step-by-step explanation:

90=25-x/2+18

combine like terms

90=43-x/2

subtract 43 from both sides

47= -×/2

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x=23.5

or

90-25= 65

65-18=47

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5 0
3 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
6. Acceleration due to gravity varies according to places of the earth, why?​
valentina_108 [34]

Answer:

The variation in apparent gravitational acceleration (g) at different locations on Earth is caused by two things.The distance between the centers of mass of two objects affects the gravitational force between them, so the force of gravity on an object is smaller at the equator compared to the poles.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
We want the following inequality to be true: IMAGE BELOW!
marta [7]

Answer:

B. X=7

Step-by-step explanation:

Because 9 greater than 7

5 0
3 years ago
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