Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Answer: y=2x-3
Step-by-step explanation:
divide both sides by 7
7y/7=(14x-21)/7
y=2x-3
The constant of proportionality is 5/9
y= kx where k is the constant of proportionality
y = 5/9 x
k = 5/9
Answer:
first one is 0.02 the second is 8
Step-by-step explanation:
Answer:
2116
Step-by-step explanation:
hope this helps :)
