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kvv77 [185]
3 years ago
12

What is the area of △JKL in square units? KJL is a triangle. The angle J is 94 degree and the angle L is 26 degree. Side JK is 2

4 and JL is 41.
Mathematics
1 answer:
Tamiku [17]3 years ago
8 0

Answer:

426.07 square units

Step-by-step explanation:

Recall that for a triangle whose angles are A,B,C  with corresponding sides a, b, c, the area G of the triangle may be computed as

G = 1/2 ab Sin C

or

G = 1/2 bc Sin A

or

G = 1/2 ac Sin B

Going by this, recall that the sum of angles in a triangle is 180 hence

94 + 26 + K = 180

120 + K = 180

Subtract 120 from both sides

K = 180 - 120

K = 60 degrees

Given that JK = 24 and JL = 41

G = 1/2 * 24 * 41 Sin 60

= 426.07 square units

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Answer:

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Step-by-step explanation:

Given

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Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

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