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2 years ago

When you skip count by 36 and 60 can it go into 144

Mathematics

1 answer:

natka813 [3]2 years ago

3 0

No because 60 would not go evenly in for it is counting in the tens

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What are the restrictions for (x^2+10x+25)/(x^2-3x-28) 0,14 -4,7 0,7 4,7

nirvana33 [79]

The answer is -4,7

The denominator can't equal zero. Factor the denominator:
x^2 - 3x - 28=
(X - 7)(x + 4); next set each set of parentheses equal to 0;
x - 7 = 0; so x=7 is one value
x + 4 = 0; so x=-4 is the other
Remember, x = 7 and x= -4 make the denominator zero, which is a "restriction" because you can't divide by zero.

5 0

3 years ago

Find the area of the triangle, also am I correct???

Ierofanga [76]

Answer:

The area of the triangle is 10.92 cm².

Step-by-step explanation:

The formula for the area of a triangle is

$A=\frac{1}{2}bh$

where b is the length of the base and h is the height. We know that b = 2.8 and h = 7.8, so you would substitute into the formula:

$A=\frac{1}{2}(2.8)(7.8)=10.92$ cm²

3 0

2 years ago

Read 2 more answers

|x-1|+2<4 solving for x

Ganezh [65]

Answer:

x < 3 and x > -1

Step-by-step explanation:

Step 1: Subtract 2 from both sides.

$|x-1| + 2 - 2 < 4 - 2$
$|x-1|$

Step 2: Solve absolute value.

We know x - 1 < 2 and x - 1 > -2.

Condition 1:

$x - 1 < 2$
$x - 1 + 1 < 2 + 1$ (Add 1 to both sides)
$x < 3$

Condition 2:

$x - 1 > -2$
$x - 1 + 1 > -2 + 1$ (Add 1 to both sides)
$x>-1$

Therefore, the answer is x < 3 and x > -1.

8 0

2 years ago

A circle is centered at N(-6, -2). The point E(-1,1) is on the circle.

galina1969 [7]

Answer:

Outside the circle

Step-by-step explanation:

Let's first write the equation of this circle: $(x-h)^2+(y-k)^2=r^2$ , where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E: