The period of oscillation of a pendulum is
![T=2 \pi \sqrt{ \frac{L}{g} }](https://tex.z-dn.net/?f=T%3D2%20%5Cpi%20%20%5Csqrt%7B%20%5Cfrac%7BL%7D%7Bg%7D%20%7D%20)
Where L is the length of the pendulum and
![g=9.81 m/s^2](https://tex.z-dn.net/?f=g%3D9.81%20m%2Fs%5E2)
the gravitational acceleration.
Re-arranging the formula and using T=1.0 s, we find the length of the pendulum:
Answer:
cross multiply
(8m)(11)=(6)(3)
88m=18
then divide by 88 on both sides
m=18/88 then reduce by 2 -----> 9/44
Step-by-step explanation:
Answer:
b = 33.546.
Step-by-step explanation:
a + b + c = 77 (1)
a - 5 = b + 5 (2)
a = 5c (3)
from equation 2:
a - b = 10
Adding this equation to equation 1:
2a + c = 87
But a = 5c so
10c + c = 87
c = 87/11 = 7.909
and a = 5*7.909 = 35.545.
b = 77 - 7.909 - 35.545
= 33.546
3.2 over 0.4 is equivalent to 8
Answer:
x=20
Step-by-step explanation:
3x+50 =6x-10
60 -=3x
x=20